=\(\frac{399x\left(45+55\right)}{1995x\left(1996-1991\right)}\)
=\(\frac{399x100}{1995x5}\)
=\(\frac{399x4x5x5}{399x5x5}\)
=\(\frac{4}{1}\)
=\(4\)
= \(\frac{17955+21945}{3982020-3972045}\)
= \(\frac{39900}{9975}\)
= \(\frac{7980}{1995}\)
= \(\frac{1596}{399}\)
= \(\frac{532}{133}\)
Aswer : \(\frac{532}{133}\)