\(\frac{35}{27}.\frac{18}{49}=\frac{35.18}{27.49}=\frac{630}{1323}=\frac{10}{21}\)
\(\frac{18}{25}.\frac{36}{125}=\frac{18.36}{25.125}=\frac{648}{3125}\)
\(\frac{35}{27}.\frac{18}{49}=\frac{35.18}{27.49}=\frac{630}{1323}=\frac{10}{21}\)
\(\frac{18}{25}.\frac{36}{125}=\frac{18.36}{25.125}=\frac{648}{3125}\)
\(\frac{35}{27}\) x\(\frac{18}{49}\)
\(\frac{18}{25}\)x\(\frac{36}{125}\)
bạn nào làm được và diễn giải mk sẽ cho 1 like
\(\frac{12}{18}+\frac{1}{3}+\frac{1}{7}+\frac{2}{8}+\frac{27}{36}+\frac{42}{49}\) tính nhanh
Rút gọn :
\(\frac{18}{30},\frac{36}{27},\frac{64}{80},\frac{45}{35}\)
Rút gọn các phân số sau :
\(\frac{18}{30},\frac{64}{80},\frac{36}{27},\frac{45}{35}\)
2.RÚT GỌN RỒI TÍNH.
\(\frac{24}{36}\)- \(\frac{6}{18}\)
\(\frac{18}{27}\)-\(\frac{2}{6}\)
\(\frac{2}{15}\)-\(\frac{5}{35}\)
\(\frac{15}{25}\)- \(\frac{3}{21}\)
Tìm số tự nhiên n sao cho :
\(\frac{54}{11}\cdot\frac{121}{27}< n< \frac{100}{21}:\frac{25}{126}\)
tính bằng cách thuận tiện nhất
a,\(\frac{6}{7}\cdot\frac{16}{15}\cdot\frac{7}{6}\cdot\frac{21}{32}\)b, \(\frac{21}{17}\cdot\frac{13}{14}\cdot56\cdot\frac{3}{42}\) c,\(\frac{7}{4}\cdot\frac{11}{21}+\frac{11}{21}\cdot\frac{5}{4}\) d,\(\frac{23}{14}\cdot\frac{6}{14}-\frac{9}{14}\cdot\frac{6}{13}\)
\(\frac{1}{2}\cdot\frac{2}{3}\cdot\frac{3}{4}\cdot\frac{4}{5}\cdot...\cdot\frac{99}{100}\)
\(\frac{1}{2}\cdot\frac{2}{3}\cdot\frac{3}{4}\cdot...\cdot\frac{2001}{2002}\cdot\frac{2002}{2003}\)=?