\(\frac{3}{4}x\frac{8}{9}x\frac{15}{16}x...x\frac{9999}{10000}\)
\(=\frac{1.3}{2^2}.\frac{2.4}{3^2}.\frac{3.5}{4^2}.....\frac{99.101}{100^2}\)
\(=\frac{1.3.2.4.3.5.....99.101}{2.2.3.3.4.4.....100.100}\)
\(=\frac{1.2.3.....99}{2.3.4.....100}.\frac{3.4.5.....101}{2.3.4.....100}\)
\(=\frac{1}{100}.\frac{101}{2}=\frac{101}{200}\)
Ủng hộ mk nha,chúc bn học tốt!!!
bn ơi mjk chưa học số có mũ bn giúp mjk nốt nha
C=\(\frac{3}{4}x\frac{8}{9}x\frac{15}{16}x.......x\frac{9999}{10000}\)
\(\frac{3}{4}\) x \(\frac{8}{9}\) x \(\frac{15}{16}\) x ......... x \(\frac{9999}{10000}\)
\(\frac{3}{4}\) x \(\frac{8}{9}\) x \(\frac{15}{16}\) x ......... x \(\frac{9999}{10000}\) =
cac ban giup minh nha
B=\(\frac{3}{4}.\frac{8}{9}.\frac{15}{16}.\frac{24}{25}...\frac{9999}{10000}=?\)
Tính P= \(\frac{3}{4}.\frac{8}{9}.\frac{15}{16}..........\frac{9999}{10000}\)
Chứng minh \(A=\frac{3}{4}+\frac{8}{9}+\frac{15}{16}+...+\frac{9999}{10000}\)không phải là số tự nhiên
Tính A = \(\frac{3}{4}.\frac{8}{9}.\frac{15}{16}...........\frac{9999}{10000}\)
giúp mk với
Thu gọn :
\(P=\frac{4}{3}.\frac{9}{8}.\frac{16}{15}.....\frac{10000}{9999}\)
B=\(\frac{3}{4}.\frac{8}{9}.\frac{15}{16}......\frac{9999}{10000}\)
Tính B
