Question

(\(\frac{3}{4}\)x-\(\frac{9}{16}\)).(1, 5+\(\frac{3}{5}\): x)=0

Answer 1

\(\left(\frac{3}{4}x-\frac{9}{16}\right)\left(1,5+\frac{3}{5}:x\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}\frac{3}{4}x-\frac{9}{16}=0\\\frac{3}{2}+\frac{3}{5}.\frac{1}{x}=0\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}\frac{3}{4}x=\frac{9}{16}\\\frac{3}{5x}=-\frac{3}{2}\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x=\frac{3}{4}\\x=-\frac{2}{5}\end{cases}}\)

Answer 2

 Có 2 trường hợp :

 Trưởng hợp 1 :( \(\frac{3}{4}\)x - \(\frac{9}{16}\)) = 0 

Ta có :  \(\frac{3}{4}\)x  = 0 + \(\frac{9}{16}\)

             \(\frac{3}{4}\)x = \(\frac{9}{16}\)

                      x = \(\frac{9}{16}\): \(\frac{3}{4}\)

               =>  x = \(\frac{3}{4}\)

Trường hợp 2 : ( 1, 5 + \(\frac{3}{5}\): x ) = 0 

                         ( \(\frac{3}{2}\)+ \(\frac{3}{5}\): x ) = 0 

                                        \(\frac{3}{5}\)  : x = 0 - \(\frac{3}{2}\)

                                          \(\frac{3}{5}\): x = \(\frac{-3}{2}\)

                                                     x = \(\frac{3}{5}\): \(\frac{-3}{2}\)

                                            = x = \(\frac{-2}{5}\)

Vậy : x = \(\frac{3}{4}\)Hoặc x = \(\frac{-2}{5}\)

Study well ^_^:))

# Cụ Maiz 

                                            

Answer 3

            Bài làm :

Ta có :

\(\left(\frac{3}{4}x-\frac{9}{16}\right)\left(1,5+\frac{3}{5}\div x\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}\frac{3}{4}x-\frac{9}{16}=0\\\frac{3}{2}+\frac{3}{5}\div x=0\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x=0,75\\x=-0,4\end{cases}}\)

Vậy x=0,75 hoặc x=-0,4