Tìm x
a \(\frac{3}{4}+\frac{1}{4}xX=2\)
b X - \(\frac{2}{3}x\frac{9}{4}=2,5-\frac{1}{2}\)
c \(2xX+\frac{1}{3}=\frac{4}{3}\)
d \(X:\frac{2}{3}+0,75=\frac{9}{4}+3\)
e \(\frac{6}{4}:X+\frac{1}{2}=\frac{9}{4}x\frac{2}{3}\)
f \(Xx\frac{3}{5}-\frac{2}{5}=3\frac{3}{4}-1\)
\(HELP\) \(ME\)\(!\)
1.
\(\frac{3}{4}x\frac{8}{5}:1\frac{1}{6}=\)\(2\frac{1}{3}x1\frac{1}{4}-\frac{7}{5}=\)\(4\frac{2}{3}+1\frac{1}{4}+2\frac{1}{3}+2\frac{3}{7}=\)2.
\(x.\frac{1}{2}=\frac{3}{4}+\frac{1}{5}\)\(x-\frac{1}{5}=\frac{2}{3}.\frac{9}{4}\)\(x.\frac{1}{5}+\frac{2}{3}=\frac{5}{4}\)\(\frac{13}{5}:x-\frac{1}{2}=\frac{4}{5}.\frac{15}{16}\)\(x:\frac{4}{9}+\frac{1}{3}=\frac{2}{5}.1\frac{13}{2}\)Chú ý: Dấu chấm là dấu nhântinh bằng cách thuật tiện nhất
\(\frac{1}{10}x\frac{2}{9}x\frac{3}{8}x\frac{4}{7}x\frac{5}{6}x\frac{6}{5}x\frac{7}{4}x\frac{8}{3}x\frac{9}{2}\)
bài 1: tìm x:
a) \(x\cdot\frac{7}{9}=\frac{2}{3}+2\frac{1}{2}\) b) \(\frac{5}{7}+x:\frac{9}{4}=\frac{4}{3}\)
Bài 1 : Tìm x
a, \(\frac{1}{2}+x+1\frac{1}{2}=3\frac{3}{4}\)
b, \(\frac{5}{6}\div x-\frac{4}{9}=\frac{3}{4}\)
\(4\frac{2}{5}+5\frac{6}{9}+2\frac{3}{4}+\frac{3}{5}+\frac{1}{3}+\frac{1}{4}\)
\(A=\left(6:\frac{3}{5}-1\frac{1}{6}x\frac{6}{7}\right):\left(4\frac{1}{5}x\frac{10}{11}+5\frac{2}{11}\right)\)\(B=\left(1-\frac{1}{2}\right)x\left(1-\frac{1}{4}\right)x.......x\left(1-\frac{1}{2015}\right)x\left(1-\frac{1}{2016}\right)\)
\(C=5\frac{9}{10}:\frac{3}{2}-\left(2\frac{1}{3}x4\frac{1}{2}-2x2\frac{1}{3}\right):\frac{7}{4}\)
\(\frac{10+\frac{9}{2}+\frac{8}{3}+\frac{7}{4}+ \frac{6}{5}+\frac{5}{6}+\frac{4}{7}+\frac{3}{8}+\frac{2}{9}+\frac{1}{10}}{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{10}+\frac{1}{11}}\)
\(4\frac{2}{5}+5\frac{6}{9}+2\frac{3}{4}+\frac{3}{5}+\frac{1}{3}+\frac{1}{4}=?\)