Question

\(\frac{3}{4}\)- \(\frac{2}{6}\)+ \(\frac{1}{3}\)-\(\frac{7}{2}\)

Answer 1

\(\frac{3}{4}-\frac{2}{6}+\frac{1}{3}-\frac{7}{2}\)
Mẫu số chung là: 12
\(=\frac{9}{12}-\frac{4}{12}+\frac{4}{12}-\frac{42}{12}\)
\(=\frac{5}{12}+\frac{4}{12}-\frac{42}{12}\)
\(=\frac{9}{12}-\frac{42}{12}\)
\(=\frac{-33}{42}\)
Đây là toán lớp 6 mà.

Answer 2

3/4-2/6+1/3-7/2

=3/4-1/3+1/3-7/2

=(3/4-7/2)+(1/3-1/3)

=-11/4+0

=-11/4

Answer 3

=9/12-4/12+2/6+21/6

=13/12+23/6

=13/12+46/12

=59/12

Answer 4

\(\frac{3}{4}-\frac{2}{6}+\frac{1}{3}-\frac{7}{2}\)

=\(\frac{7}{12}+\frac{-19}{6}\)

=\(\frac{-31}{12}\)