Ta có :\(\frac{3^2.3^8}{27^3}=3^x\)
\(\Rightarrow\frac{3^{10}}{\left(3^3\right)^3}=3^x\)
\(\Rightarrow\frac{3^{10}}{3^9}=3^x\)
\(\Rightarrow3^1=3^x\)
\(\Rightarrow x=1\)
Vậy \(x=1\)
\(\frac{3^2.3^8}{27^3}\)=\(\frac{3^{10}}{27^3}\)=\(\frac{3^{10}}{\left(3^3\right)^3}\)=\(\frac{3^{10}}{3^9}\)=3
Mà \(\frac{3^2.3^8}{27^3}\)=3x
\(\Rightarrow\)3=3x
\(\Rightarrow\)x=1
Vậy x=1.
\(\frac{3^2.3^8}{27^3}=3^x\)
Tìm x
\(\frac{3^2.3^8}{27^3}\)=\(^{3^x}\)
Tìm x biết \(\frac{3^2.3^8}{27^3}=3^x\)
Tìm số nguyên x, nếu biết:
1)\(4.3^{x-1}+2.3^{x+2}=4.3^6+2.3^9\)
2)\(\frac{5}{3}.8^{x+2}-\frac{3}{5}.8^x=\frac{5}{3}.8^{11}-\frac{3}{5}.8^9\)
3)\(\left(\frac{1}{3}+\frac{1}{6}\right).2^{x+4}-2^x=2^{13}-2^{10}\)
Mấy bn giúp mk nha!!! lm câu nào cg đc hết á, cảm ơn nha!!!!!
:D
Mọi người giúp mình bài tìm x
1) (x-2/9)^3 = (8/27)^2
2)2.3^x -405 = 3^x-1
3)4/3 : 0,8 = 0,75x : (-1,5)
Mọi người giúp mình bài tìm x
1) (x-2/9)^3 = (8/27)^2
2)2.3^x -405 = 3^x-1
3)4/3 : 0,8 = 0,75x : (-1,5)
đang cần gấp chìu nộp cho cô òi ( ai nhanh + đúng = 20 ticks
bài 1 tính
4.\(\left(\frac{-1}{2}\right)^3-2.\left(\frac{-1}{2}\right)^2+3.\left(\frac{-1}{2}\right)+1\)1
bài 2 : tìm x
a)\(\frac{37-x}{x+13}=\frac{3}{7}\)
b) | x - \(\frac{1}{2}\)| - \(\sqrt{\frac{1}{9}}=\sqrt{\frac{1}{4}}\)
c) \(2^{3x+2}=4^{x+5}\)
d) \(\frac{3^2.3^8}{27^3}=3^x\)
bài 3: tìm x,y
a)\(\frac{2x}{3y}=-\frac{1}{3}\)và -2x+3y=7
a)A=\(\frac{16^3.3^{10}+120.6^9}{4^6.3^{12}+6^{11}}\) b)B=\(\frac{45}{19}-\left(\frac{1}{2}\left(\frac{1}{3}+\left(\frac{1}{4}\right)^{-1}\right)^-\right)^{-1}\) c)C=\(\frac{5.4^{15}.9^9-4.3^{20}.8^9}{5.2^{10}.6^{19}-7.2^{29}.27^6}\)
d)D=\(\frac{2^{21}.3^5-4^6.81}{\left(2^2.3\right)^6+8^4.3^5}\) e) E=\(\left(6^9.2^{10}+12^{10}\right):\left(2^{19}.27^3+15.4^9.9^4\right)\)
f) F=\(\frac{3^6.45^4-15^{13}.5^{-9}}{27^4.24^3+45^6}\) g)G=\(\frac{\left(\frac{2}{5}\right)^7.5^7+\left(\frac{9}{4}\right)^3:\left(\frac{3}{16}\right)^3}{2^7.5^2+512}\) h)H=\(x+\frac{0,2-0,375+\frac{5}{11}}{-0,3+\frac{9}{16}-\frac{15}{22}}\)với x=-1/3
\(3^x=\frac{6}{1}.\frac{9}{2}.\frac{12}{3}...\frac{27}{8}\)
