Các câu hỏi tương tự
\(\frac{9}{14}\cdot y=\frac{7}{14}\cdot\frac{4}{7}\)
Mình mong ai đo trả lời giúp mình:
Tinh bằng cách thuận tiện
\(\frac{9}{25}\cdot\frac{5}{7}+\frac{6}{25}\cdot\frac{20}{28}+2\cdot\frac{1}{5}:\frac{7}{5}-\frac{3}{7}-\frac{2}{7}\)
a)\(\frac{11}{9}+\frac{7}{6}\cdot\left(2-\frac{1}{3}\right)\)
b)\(1\frac{1}{21}:\left(15,75-15\frac{1}{4}\right)+2\frac{1}{12}:\left(7\frac{3}{4}-7,25\right)\)
a.\(x+x\cdot\frac{1}{3}:\frac{2}{9}+x:\frac{2}{7}=252\)
b.\(\left(3\cdot x-0.8\right):x+14.5=15\)
\(\left(1-\frac{1}{4}\right)\left(1-\frac{1}{9}\right)\left(1-\frac{1}{16}\right)\cdot....\cdot\left(1-\frac{1}{256}\right)\cdot x=\frac{108}{7}\)
\(\frac{4}{3}\cdot\frac{4}{7}+\frac{4}{7}\cdot\frac{4}{11}+.....+\frac{4}{95}\cdot\frac{4}{99}\)
\(\frac{4}{3}\cdot\frac{9}{8}\cdot......\cdot\frac{100}{99}-\frac{9}{11}\)* = dấu nhân
bài 1: tìm x:
a) \(x\cdot\frac{7}{9}=\frac{2}{3}+2\frac{1}{2}\) b) \(\frac{5}{7}+x:\frac{9}{4}=\frac{4}{3}\)
\(\frac{5}{6}+\frac{1}{3}\cdot x=\frac{8}{9}b,120+x\cdot2=7\cdot x+45\)