\(\frac{30}{43}=\frac{1}{\frac{43}{30}}=\frac{1}{1+\frac{13}{30}}=\frac{1}{1+\frac{1}{\frac{30}{13}}}=\frac{1}{1+\frac{1}{2+\frac{4}{13}}}=\frac{1}{1+\frac{1}{2+\frac{1}{\frac{13}{4}}}}\)\(=\frac{1}{1+\frac{1}{2+\frac{1}{3+\frac{1}{4}}}}\)
Suy ra: a=1;b=2;c=3;d=4