Các câu hỏi tương tự
\(P=\left(\frac{1}{\sqrt{x}-\sqrt{x-1}}-\frac{x-3}{\sqrt{x-1}-\sqrt{2}}\right)\left(\frac{2}{\sqrt{2}-\sqrt{x}}-\frac{\sqrt{x}+\sqrt{2}}{\sqrt{2x}-x}\right)\)
a)Rut gon P?
b)Tinh gia tri cua P voi \(x=3-2\sqrt{2}\)?
\(\frac{\sqrt{3}+\sqrt{2}-1}{2+\sqrt{6}}+\frac{\sqrt{2}-\sqrt{3}}{\sqrt{2}+1}\left(\frac{\sqrt{3}}{2-\sqrt{6}}+\frac{\sqrt{3}}{2+\sqrt{6}}\right)-\frac{1}{\sqrt{2}}\)
mn giai nhanh ho mk nha ai nhanh nhat mk cho 3 k
Thuc hien phep tinh:
B=\(\frac{2+\sqrt{3}}{\sqrt{2}+\sqrt{2+\sqrt{3}}}+\frac{2-\sqrt{3}}{\sqrt{2}-\sqrt{2-\sqrt{3}}}\)
\(\frac{\sqrt{13+2\sqrt{11}}+\sqrt{13-2\sqrt{11}}}{\sqrt{13+5\sqrt{5}}}-\sqrt{3-2\sqrt{2}}\)
Giup minh voi
\(\frac{1+\frac{\sqrt{3}}{2}}{1+\sqrt{1+\frac{\sqrt{3}}{2}}}+\frac{1-\frac{\sqrt{3}}{2}}{1-\sqrt{1-\frac{\sqrt{3}}{2}}}\)
Hay cho minh thay canh tay cua may ban gioi toan naooooo
Tinh gia tri bieu thuc
Chứng minh:
\(\frac{2+\sqrt{3}}{\sqrt{2}+\sqrt{2+\sqrt{3}}}+\frac{2-\sqrt{3}}{\sqrt{2}-\sqrt{2-\sqrt{3}}}=\sqrt{2}\)
Tính:a) frac{2}{3+2sqrt{2}}-frac{7}{1-2sqrt{2}}+frac{4}{sqrt{5}-1}+sqrt{8}-2b) frac{1}{1+sqrt{2}}+frac{1}{sqrt{3}+sqrt{2}}+frac{1}{sqrt{4}+sqrt{5}}c) sqrt{4-2sqrt{3}}+2sqrt{3}d) Asqrt{2-sqrt{3}}+sqrt{2+sqrt{3}}e) Bsqrt{frac{2}{2+sqrt{3}}}Các bạn giải đc câu nào thì giải dùm mk nha!!! Thanks :))))
Đọc tiếp
Tính:
a) \(\frac{2}{3+2\sqrt{2}}-\frac{7}{1-2\sqrt{2}}+\frac{4}{\sqrt{5}-1}+\sqrt{8}-2\)
b) \(\frac{1}{1+\sqrt{2}}+\frac{1}{\sqrt{3}+\sqrt{2}}+\frac{1}{\sqrt{4}+\sqrt{5}}\)
c) \(\sqrt{4-2\sqrt{3}}+2\sqrt{3}\)
d) \(A=\sqrt{2-\sqrt{3}}+\sqrt{2+\sqrt{3}}\)
e) \(B=\sqrt{\frac{2}{2+\sqrt{3}}}\)
Các bạn giải đc câu nào thì giải dùm mk nha!!! Thanks :))))
1) Chứng minh: \(2\sqrt{n}-3< \frac{1}{\sqrt{2}}+\frac{1}{\sqrt{3}}+...+\frac{1}{\sqrt{n}}< 2\sqrt{n}-2\forall n\ge2\)
2) Thu gọn: \(A=5\left(\sqrt{2+\sqrt{3}}+\sqrt{3-\sqrt{5}}-\sqrt{\frac{5}{2}}\right)^2+\left(\sqrt{2-\sqrt{3}}+\sqrt{3+\sqrt{5}}-\sqrt{\frac{3}{2}}\right)^2\)
Chứng minh rằng:
\(\frac{2+\sqrt{3}}{\sqrt{2}+\sqrt{2+\sqrt{3}}}+\frac{2-\sqrt{3}}{\sqrt{2}-\sqrt{2-\sqrt{3}}}=\sqrt{2}\)