\(\frac{2\cos^2\alpha-1}{\sin\alpha+\cos\alpha}=\frac{2\cos^2\alpha-\left(\sin^2\alpha+\cos^2\alpha\right)}{\sin\alpha+\cos\alpha}\)\(=\frac{\cos^2\alpha-\sin^2\alpha}{\sin\alpha+\cos\alpha}=\cos\alpha-\sin\alpha\)
CMR\(\frac{1-2\cos^2\alpha}{1+2\sin\alpha.\cos\alpha}=\frac{\sin\alpha-\cos\alpha}{\sin\alpha+\cos\alpha}\)
1. Chứng minh rằng: \(\frac{1-2\sin.\cos\alpha}{sin^2\alpha-\cos^2\alpha}=\frac{sin\alpha-\cos\alpha}{sin\alpha+\cos\alpha}\) (\(\alpha\ne45^o\))
2. Chứng minh: \(\cos^4\alpha+\sin^2\alpha.\cos^2\alpha+\sin^2\alpha\) không phụ thuộc vào x
Chứng minh các hệ thức sau:
a) \(\frac{1-cos\alpha}{sin\alpha}=\frac{sin\alpha}{1+cos\alpha}\)
b) \(tan^2\alpha-sin^2\alpha=tan^2\alpha.sin^2\alpha\)
c) \(\frac{1-tan\alpha}{1+tan\alpha}=\frac{cos\alpha-sin\alpha}{cos\alpha+sin\alpha}\)
Chứng minh:
a)\(\cos^4\alpha-sin^4\alpha=2cos^2\alpha-1\)
b)\(\frac{cos\alpha}{1-sin\alpha}=\frac{1+sin\alpha}{cos\alpha}\)
c)\(\frac{\left(sin\alpha+cos\alpha\right)^2-\left(sin\alpha-cos\alpha\right)^2}{sin\alpha.cos\alpha}=4\)
Mình cần gấp!!!
CMR: \(\frac{\sin^2\alpha}{\cos\alpha\left(1+\tan\alpha\right)}-\frac{\cos^2\alpha}{\sin\alpha\left(1+\cot\alpha\right)}=\sin\alpha-\cos\alpha\)
Cho tan \(\alpha\)=\(\frac{3}{5}\). Tính
A= \(\frac{\sin\alpha+\cos\alpha}{\sin\alpha-\cos\alpha}\)
B=\(\frac{\sin\alpha\cdot\cos\alpha}{\sin^2\alpha-\cos^2\alpha}\)
C=\(\frac{\sin^3\alpha\cdot\cos^3\alpha}{2\sin\alpha\cdot\cos^2\alpha+\cos\alpha\cdot\sin^2\alpha}\)
Giúp mình với . MÌnh cảm ơn
\(\left(1+\tan^2\alpha\right)\cos^2\alpha+\left(1+\cot^2\alpha\right)\sin^2\alpha\)
\(=\left(1+\frac{\sin^2\alpha}{\cos^2\alpha}\right)\cos^2\alpha+\left(1+\frac{\cos^2\alpha}{\sin^2\alpha}\right)\sin^2\alpha\)
\(=\cos^2\alpha+\sin^2\alpha+\sin^2\alpha+\cos^2\alpha\)
\(=2\sin^2\alpha+2\cos^2\alpha\)
đúng hay sai zậy các bạn
CMR: \(\frac{\sin^4\alpha-\cos^2\alpha+2\cos^4\alpha-\cos^6\alpha}{\cos^4\alpha-\sin^2\alpha+2\sin^4\alpha-\sin^6\alpha}=\tan^6\alpha\)
1) Cho: \(\tan\alpha=\frac{1}{2}\). Tính \(\frac{\cos\alpha+\sin\alpha}{\cos\alpha-\sin\alpha}\)
2) Cho: \(\cos\beta=2\sin\beta.\) Hãy tính: \(\sin\beta.\cos\beta\)
3)Chứng minh hệ thức:
a/ \(\frac{1+\cos\alpha}{\sin\alpha}=\frac{\sin\alpha}{1-\cos\alpha}\)
b/ \(\cot^2\alpha-\cos^2\alpha=\cot^2\alpha.\cos\alpha\)
rút gọn biểu thức sau:
b, \(\frac{\left(\cos\alpha-\sin\alpha\right)^2-\left(\cos\alpha-\sin^2\alpha\right)}{\cos\alpha.\sin\alpha}\)
c,\(C=\sin^6\alpha+\cos^6\alpha+3\sin^6\alpha.\cos^2\alpha\)
