\(\frac{27^2.8^5}{6^6.32^3}=\frac{\left(3^3\right)^2.\left(2^3\right)^5}{2^6.3^6.\left(2^5\right)^3}\)
\(=\frac{3^6.2^{15}}{2^6.3^6.2^{15}}\)
\(=\frac{1}{2^6}\)
27^2.8^5/6^6.32^3
giải chi tiết giúp mk vs nha
Rút gọn
a) A = \(\frac{2^5.3^7.5^9}{2^3.3^5.5^7}\) b) B = \(\frac{27^2.8^5}{6^6.32^3}\) c) C = \(\frac{3^{10}.11+3^{10}.5}{3^9.2^4}\) d) D = \(\frac{4^5.9^4+2.6^9}{2^{10}.3^8+6^8.20}\) e) F = \(\frac{2^{10}.13+2^{10}.65}{2^8.104}\)
Dấu . là dấu nhân đấy mình viết theo kiểu cấp 2 mà
Bạn nào làm nhanh mình k cho
Tính nhanh (nếu có thể):
a,\(\frac{27^2.8^5}{66.32^3}\)
b, \(\frac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}\)
c, \(\frac{\left(17\frac{8}{19}-16\frac{9}{18}\right).\left(17,5+16\frac{17}{51}-32\frac{15}{22}\right)}{\frac{7}{3.13}+\frac{7}{13.3}+\frac{7}{23.33}}\)
Tính \(A=\frac{5.4^{15}.9^9-4.3^2.8^9}{5.2^9.6^{19}-7.2^{29}.27^6}\)
\(\frac{5^2.3^3-25.17}{25.3^2-5^2.8}\)
\(\frac{9^2.8^6}{16^4.3^{13}}+\frac{\left(3^2\right)^2.\left(2^3\right)^6}{\left(2^4\right)^4.3^{13}}=?\)
C=5.4^6.9^4-3^9.(-8)^4/4.2^13.3^8+2.8^4.(-27)^3
Tính:
a) \(\frac{\frac{3}{5}+\frac{3}{27}-\frac{3}{9}-\frac{3}{11}}{\frac{4}{5}+\frac{4}{27}-\frac{4}{9}-\frac{4}{11}}\)
b) \(\frac{5-\frac{5}{3}-\frac{5}{27}}{8-\frac{8}{3}-\frac{8}{27}}:\frac{15+\frac{15}{121}-\frac{15}{11}}{16+\frac{16}{121}-\frac{16}{11}}\)
c) \(\frac{1}{2}:\left(\frac{-3}{2}\right):\frac{4}{3}:\left(\frac{-5}{4}\right):\frac{6}{5}:\left(\frac{-7}{6}\right):...:\left(\frac{-101}{100}\right)\)
Mọi người nhớ đánh nhanh câu trả lời giúp mình nhé!!
tìm x biết
( \(6\frac{3}{7}\)- \(\frac{0.75x-2}{0.35}\)) . 2.8=10
