Question

\(\frac{2^5\times7+2^5}{2^5\times5^2-2^5\times3}\)

Help me!!!

Answer 1

\(\frac{2^5\times7+2^5}{2^5\times5^2-2^5\times3}=\frac{2^5\times\left(7-1\right)}{2^5\times25-2^5\times3}=\frac{2^5\times8}{2^5\times\left(25-3\right)}=\frac{2^5\times8}{2^5\times22}=\frac{8}{22}=\frac{4}{11}\)

Answer 2

\(\frac{2^5x7+2^5}{2^5x5^2-2^5x3}\)= \(\frac{2^5\left(7+1\right)}{2^5\left(5^2-3\right)}\)= \(\frac{2^5.8}{2^5.22}\)=\(\frac{8}{22}\)=\(\frac{4}{11}\)