Question

\(\frac{2}{3}-\frac{1}{3}.\left(x-\frac{3}{2}\right)-\frac{1}{2}.\left(2x+1\right)=\)5

tìm x: 

Answer 1

\(\frac{1}{3}\left(x-\frac{3}{2}\right)-\frac{1}{2}\left(2x+1\right)=\frac{2}{3}-5=-\frac{13}{3}\)

\(\frac{1}{3}x-\frac{1}{2}-x-\frac{1}{2}=-\frac{13}{3}\)

\(-\frac{2}{3}x-1=-\frac{13}{3}\)

\(-\frac{2}{3}x=-\frac{13}{3}+1=\frac{-10}{3}\)

\(x=-\frac{10}{3}:-\frac{2}{3}=5\)

Answer 2

=2/3-x/3+1/2-x-1/2=5

<=>2/3-x/3-x=5

<=>-x/3-x=5-2/3

<=>-4x/3=13/3

<=>-4x=13

<=>x=-13/4