Các câu hỏi tương tự
\(\frac{2^2}{1.3}+\frac{3^2}{2.4}+\frac{4^2}{3.5}+...+\frac{100^2}{99.101}\)
Giúp mình với
\(\frac{2^2}{1.3}+\frac{3^2}{2.4}
+\frac{4^2}{3.5}+...+\frac{100^2}{99.101}\)
Giúp mình với.
HELP ME!
\(1.\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+...+\frac{2}{99.101}\)
\(2.\frac{4}{2.4}+\frac{4}{4.6}+\frac{4}{6.8}+...+\frac{4}{2008.2010}\)
\(3.\frac{1}{16}+\frac{1}{48}+\frac{1}{96}+...+\frac{1}{19600}\)
\(\frac{x}{200}=\frac{1^2}{1.2}.\frac{2^2}{2.3}...\frac{99^2}{99.100}\) tìm x nha
\(\frac{x}{101}=\frac{2^2}{1.3}.\frac{3^2}{2.4}...\frac{100^2}{99.101}\)
Tính tổng:
a,\(\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+...+\frac{2}{99.101}\)
b,\(\frac{5}{1.3}+\frac{5}{3.5}+\frac{5}{5.7}+...+\frac{5}{99.101}\)
\(\frac{2^2}{1.3}.\frac{3^2}{2.4}.\frac{4^2}{3.5}.\frac{5^2}{4^6}\)
tinh tổng
a)\(\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+...+\frac{2}{99.101}\)
b)\(\frac{5}{1.3}+\frac{5}{3.5}+\frac{5}{5.7}+...+\frac{5}{99.101}\)
\(\frac{2^2}{1.3}.\frac{3^2}{2.4}.\frac{4^2}{3.5}...\frac{59^2}{58.60}\)
a)\(\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+...+\frac{2}{99.101}\)
b) \(\frac{5}{1.3}+\frac{5}{3.5}+\frac{5}{5.7}+...+\frac{5}{99.101}\)
( Tính tổng )