1.giải hệ phương trình
\(5x^2+6x+9=1x^2+2x^2+....+99x^8\)
\(5x^4+9y^3-3z^2+8x+3y=1x^2+2y^2+3z^4+.....+1999x^2\)
\(9y^8+6y^5+7x^3+9\sqrt[15]{x^4}=\sqrt[9]{x}+9\sqrt[10]{z}+......+888\sqrt[55]{x}\)
\(\frac{1}{\sqrt[9]{x}}+\frac{2}{\sqrt[8]{y}}+...+\frac{9}{\sqrt{x}}=\frac{1}{\sqrt[100]{x}-\sqrt[99]{y}-...-\sqrt{z}}\)
\(\sqrt[3]{2x^2}+.....+\sqrt[3]{23z^2}=\sqrt{5x}+\sqrt{7y}+\sqrt{11z}+...+\sqrt{97x}\)
Tìm x,y,z
THÁCH THỨC NGƯỜI THÔNG MINH GIẢI BÀI NÀY
\(\frac{1}{x}+\frac{1}{y}+\frac{1}{z}=1\) . Tìm Min \(\sqrt{\frac{2x^{3}+3y^{2}}{x+4y}}+\sqrt{\frac{2y^{3}+3z^{2}}{y+4z}}+\sqrt{\frac{2z^{3}+3x^{2}}{z+4x}}\)
Giải hệ phương trình :
a) \(\hept{\begin{cases}x^2+y^2=1\\x^9+y^9=1\end{cases}}\)
b)\(\hept{\begin{cases}\sqrt{x}+\sqrt{y}+\sqrt{z}=2014\\\frac{1}{3x+2y}+\frac{1}{3y+2z}+\frac{1}{3z+2x}=\frac{1}{x+2y+3z}+\frac{1}{y+2x+3x}+\frac{1}{z+2x+3y}\end{cases}}\)
Giải phương trình:
\(a)\sqrt{x^2+2x+4}\ge x-2\\ b)x=\sqrt{x-\frac{1}{x}}+\sqrt{x+\frac{1}{x}}\\ c)\sqrt{x+2+3\sqrt{2x-5}}+\sqrt{x-2\sqrt{2x-5}}\\ d)x+y+z+4=2\sqrt{x-2}+4\sqrt{y-3}+6\sqrt{z-5}\\ e)\sqrt{x}+\sqrt{y-1}+\sqrt{z-2}=\frac{1}{2}\left(x+y+z\right)\)
\(T_{max}=\frac{x}{x+\sqrt{2x+yz}}+\frac{y}{y+\sqrt{3y+xz}}+\frac{z}{z+\sqrt{3z+xy}}\left(x+y+z=3\right)\)
giải phương trình
a) \(\left(x+\frac{5-x}{\sqrt{x}+1}\right)^2+\frac{16\sqrt{x}\left(5-x\right)}{\sqrt{x}+1}-16\)\(=0\)
b) \(\sqrt{2x-\frac{3}{x}}+\sqrt{\frac{6}{x}-2x}=1+\frac{3}{2x}\)
c) \(\sqrt{2x+1}+\frac{2x-1}{x+3}-\left(2x-1\right)\sqrt{x^2+4}-\sqrt{2}=0\)
d) \(\sqrt{x+2+3\sqrt{2x-5}}+\sqrt{x-2-\sqrt{2x-5}}=2\sqrt{2}\)
35Cho biểu thức
P=\(\left[\left(\frac{1}{\sqrt{x}}+\frac{1}{\sqrt{y}}\right)\frac{2}{\sqrt{x}+\sqrt{y}}+\frac{1}{x}+\frac{1}{y}\right]:\frac{\sqrt{x^3}+y\sqrt{x}+x\sqrt{y}+\sqrt{y^3}}{\sqrt{xy^3}+\sqrt{x^3y}}\)
a) Rút gọn P
b)Cho xy=16 . Tìm Min P
34 Cho biểu thức
P=\(\frac{x}{\sqrt{xy}-2y}-\frac{2\sqrt{x}}{x+\sqrt{x}-2\sqrt{xy}-2\sqrt{y}}-\frac{1-x}{1-\sqrt{x}}\)
a) Rút gọn P
b)Tính P biết 2x^2+y^2-4x-2xy+4=0
đặt \(P=\frac{1}{\sqrt{x^5-x^2+3xy+6}}+\frac{1}{\sqrt{y^5-y^2+3yz+6}}+\frac{1}{\sqrt{z^5-z^2+3zx+6}}\)
ta có:\(\left(x^3+2x^2+3x+3\right)\left(x-1\right)^2\ge0\)
\(\Leftrightarrow x^5-x^2\ge3x-3\)
cmtt=>\(y^5-y^2\ge3y-3;z^5-z^2\ge3z-3\)
\(\Rightarrow P\le\frac{1}{\sqrt{3x-3+3xy+6}}+\frac{1}{\sqrt{3y-3+3yz+6}}+\frac{1}{\sqrt{3z-3+3zx+6}}\)
\(=\frac{1}{\sqrt{3\left(x+xy+1\right)}}+\frac{1}{\sqrt{3\left(y+yz+1\right)}}+\frac{1}{\sqrt{3\left(z+zx+1\right)}}\)
áp dụng bunhia ta có:
\(3\left(x+xy+1\right)\ge\left(\sqrt{x}+\sqrt{xy}+1\right)^2\)
cmtt\(\Rightarrow P\le\frac{1}{\sqrt{x}+\sqrt{xy}+1}+\frac{1}{\sqrt{y}+\sqrt{yz}+1}+\frac{1}{\sqrt{z}+\sqrt{zx}+1}\)
đặt \(\sqrt{x}=a;\sqrt{y}=b;\sqrt{z}=c\)
\(\Rightarrow\frac{1}{\sqrt{x}+\sqrt{xy}+1}+\frac{1}{\sqrt{y}+\sqrt{yz}+1}+\frac{1}{\sqrt{z}+\sqrt{zx}+1}=\frac{1}{a+ab+1}+\frac{1}{b+bc+1}+\frac{1}{c+ca+1}\)
\(=\frac{abc}{a+ab+abc}+\frac{1}{b+bc+1}+\frac{b}{bc+abc+b}=\frac{bc}{bc+b+1}+\frac{b}{bc+b+1}+\frac{1}{bc+b+1}=1\)
\(\Rightarrow P\le1\)
giải pt
1. \(x^2-5x+14=4\sqrt{x+1}\)
2. \(x^4+x^2+1=y^2\)với x, y nguyên
3. \(xy-2x+3y=21\)
4. \(x=\sqrt{x-\frac{1}{x}}+\sqrt{1-\frac{1}{x}}\)
5. \(\frac{36}{\sqrt{x-2}}+\frac{4}{\sqrt{y-1}}=28-4\sqrt{x-2}-\sqrt{y-1}\)
6. \(2\left(x^2+2x+3\right)=5\sqrt{x^3+3x^2+3x+2}\)