\(\frac{19}{2}+\frac{6}{8}.\frac{2}{3}:\left(1-\frac{3}{2}\right)\)
\(=\frac{19}{2}+\frac{6}{8}.\frac{2}{3}:\frac{-1}{2}\)
\(=\frac{19}{2}+\frac{1}{2}:\frac{-1}{2}\)
\(=\frac{19}{2}+\left(-1\right)\)
\(=\frac{19}{2}-\frac{-2}{2}\)
\(=\frac{17}{2}\)
\(a,\left(1-\frac{1}{2}\right)\cdot\left(1-\frac{1}{3}\right)\cdot\left(1-\frac{1}{4}\right)\cdot......\left(1-\frac{1}{18}\right)\cdot\left(1-\frac{1}{19}\right)\cdot\left(1-\frac{1}{20}\right)\)
1,Tính nhanh
a,3x\(\left(\frac{1}{7}+\frac{1}{3}-\frac{3}{14}\right):\frac{11}{14}\)
b,\(\left(\frac{21}{8}+\frac{1}{2}\right):\frac{5}{6}\)
3,Tìm x,biết
a,\(\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+......+\frac{2}{x\cdot\left(x+1\right)}=\frac{2016}{2018}\)
b,720:\(720:[41-\left(2\cdot x-5\right)]=120\)
Tính nhanh:
\(\frac{9,1+10,2+...+17,9+19}{\left(1-\frac{2}{42}\right)\cdot\left(1-\frac{2}{56}\right)\cdot...\cdot\left(1-\frac{2}{2550}\right)\cdot\left(1-\frac{2}{2652}\right)}\cdot\frac{265}{357}\)
Làm nhanh cho mình trước 14h30p 30/7/2016
Ai làm được cho 5 lần tick
\(\left(1+\frac{1}{2}\right)\cdot\left(1+\frac{1}{3}\right)\cdot\left(1+\frac{1}{4}\right)\cdot....\cdot\left(1+\frac{1}{98}\right)\cdot\left(1+\frac{1}{99}\right)=\)?
\(\left(6\frac{3}{5}-8\cdot0,125+\frac{2}{15}\cdot0,3\right)\cdot\frac{3}{14}\)
Tính giá trị biểu thức :
\(\left(1-\frac{1}{2}\right)\cdot\left(1-\frac{1}{3}\right)\cdot\left(1-\frac{1}{4}\right)\cdot....\cdot\left(1-\frac{1}{99}\right)\cdot\left(1-\frac{1}{100}\right)\)
Bài 1:
\(a,\left(x-\frac{1}{2}\right)\cdot\left(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+......+\frac{1}{90}\right)=\frac{1}{3}\)
\(b,\frac{1}{1\cdot6}+\frac{1}{6\cdot11}+.....+\frac{1}{96\cdot101}=\frac{1}{10\cdot x}\)
\(c,460+85\cdot4=\frac{x+175}{5}+30\)
\(d,\left(x-5\right)\cdot\left(10-9\frac{40}{41}\right):\left(1-\frac{81}{82}\right):\left(1-\frac{204}{205}\right)=2050\)
a)\(\frac{11}{9}+\frac{7}{6}\cdot\left(2-\frac{1}{3}\right)\)
b)\(1\frac{1}{21}:\left(15,75-15\frac{1}{4}\right)+2\frac{1}{12}:\left(7\frac{3}{4}-7,25\right)\)
\(\left(1+\frac{1}{2}\right)\cdot\left(1+\frac{1}{3}\right)\cdot\left(1+\frac{1}{4}\right)\cdot...\cdot\left(1+\frac{1}{10}\right)\) = ?
