ban ơi là \(\frac{1^{2005}}{8}\)hay \(\left(\frac{1}{8}\right)^{2005}\)
1/8^2005.9^1005-96^2:24^2
=9/8^2005-4^2
den doan nay thi em chiu roi em moi hoc lop 6 thoi a
\(\left(\frac{1}{9}\right)^{^{2005}}.9^{2005}-96^2:24^2\) = ?
Bài 2 :(1/9)^2005 . 9^2005 . 96^2 : 24^2
Bài 3 : Tìm các số a,b biết : a/2=b/3 và a+b = -15
tính hợp lí các biểu thức sau
\(\left(\frac{1}{9}\right)^{2005}.9^{2005}-96^2:24^2\)
\(16\frac{2}{7}:\left(\frac{-3}{5}\right)-28\frac{2}{7}:\left(\frac{-3}{5}\right)\)
\(\left(-2\right)^3.\left(\frac{3}{4}-0.25\right):\left(2\frac{1}{4}-1\frac{1}{6}\right)\)
Tính: S
S= \(\frac{2}{2005+1}\) + \(\frac{2^2}{2005^2+1}\)+ \(\frac{2^3}{2005^{2^2}+1}\)+ \(\frac{2^4}{2005^{2^3}+1}\)+ .... + \(\frac{2005^{2006}}{2005^{2^{2005}}+1}\)+ .... + \(\frac{2^{n+1}}{2005^{2^n}+1}\)
Tính:
S = \(\frac{2}{2005+1}\)+ \(\frac{2^2}{2005^2+1}\)+ \(\frac{2^3}{2005^{2^2}+1}\)+ \(\frac{2^4}{2005^{2^3}+1}\)+ ...+ \(\frac{2^{n+1}}{2005^{2^n}+1}\)+ ...+ \(\frac{2^{2006}}{2005^{2^{2005}}+1}\)
Bài 1: Thực hiện phép tính( bằng cahcs hợp lí nếu có thể)
\(a)\frac{7}{25}+\frac{4}{13}-\frac{5}{2}+\frac{18}{25}-1\frac{4}{13}\)
\(b)12-8.\left(\frac{3}{2}\right)^3\)
\(c)100\times\sqrt{0,04}+\sqrt{\frac{25}{16}}\)
\(d)\frac{1}{4}+\frac{3}{4}.\frac{5}{6}\)
\(e)3,75.7,2+2,8.3,75\)
\(f)\frac{1}{2}\sqrt{4}-\sqrt{25}\)
\(g)(\frac{1}{9})^{2005}.9^{2005}-96^2:24^2\)
\(h)\frac{15}{34}+\frac{7}{21}+\frac{19}{34}-\frac{20}{15}+\frac{3}{7}\)
\(k)\left(-3,5\right).\left(-7,2\right)+\left(-3,15\right).12,4+4,8.\left(-3,15\right)\)
\(l)16\frac{2}{7}:\left(-\frac{2}{5}\right)-28\frac{2}{7}:\left(-\frac{2}{5}\right)\)
\(m)\left(-\frac{1}{2}\right)^3+\frac{1}{2}:5\)
\(n)1\frac{1}{23}+\frac{2}{21}-\frac{1}{23}+\frac{19}{21}+2013^0\)
\(h)\frac{-5}{9}.\left(\frac{3}{10}-\frac{2}{5}\right)\)
\(i)\frac{1}{2}\sqrt{64}-\sqrt{\frac{4}{25}+1^{2012}}\)
Giải Hộ Mk vs Mk đng cần gấp để nộp
HELP MEEEEEEEEEEEEEEEEEEEE
1, Tìm chữ số tận cùng của A=19^5^1^8^9^0 + 2^9^1^9^6^9 (lũy thừa tầng)
2, Cho B= \(\frac{1}{3}+\frac{1}{3^2}+\frac{1}{3^3}+\frac{1}{3^4}+...+\frac{1}{3^{2004}}+\frac{1}{3^{2005}}\)
CMR: B< \(\frac{1}{2}\)
Cho \(\frac{a}{b}=\frac{c}{d}\). CMR : \(\frac{2.a^{2005}+5.b^{2005}}{2.c^{2005}+5.d^{2005}}=\frac{\left(a+b\right)^{2005}}{\left(c+d\right)^{2005}}\)
Tìm x,y biết
a,\(\left(2^3\right)^{1^{2005}}\cdot x+2005^0\cdot x=994-15:3+1^{2025}\)
b,\(2^x+2^{x+1}+2^{x+2}+2^{x+3}=480\)
c,\(2024^{|x-1|+y^2-1}\cdot3^{2024}=9^{1012}\)
