Question

 

\(\frac{1717}{1212}x+\frac{1717}{2020}x+\frac{1717}{3030}x=\frac{17}{6}\)   

giải cả bài nhé

Answer 1

\(\frac{1717}{1212}x+\frac{1717}{2020}x+\frac{1717}{3030}x=\frac{17}{6}\)

=>\(\left(\frac{1717}{1212}+\frac{1717}{2020}+\frac{1717}{3030}\right)x=\frac{17}{6}\)

=>\(\frac{17}{6}x=\frac{17}{6}\)

=>x=1

Answer 2

\(\frac{1717}{1212}x+\frac{1717}{2020}x+\frac{1717}{3030}x=\frac{17}{6}\Rightarrow\left(\frac{17}{12}+\frac{17}{20}+\frac{17}{30}\right)x=\frac{17}{6}\Rightarrow\frac{17}{6}x=\frac{17}{6}\Rightarrow x=1\)