\(=\frac{3.5.\left(2^2\right)^{12}.\left(3^2\right)^7-2^2.3^{15}.\left(2^3\right)^8}{19.2^{24}.3^{14}-2.3.\left(2^2\right)^{12}.\left(3^3\right)^5}\)
\(=\frac{3.5.2^{24}.3^{14}-2^2.3^{15}.2^{24}}{19.2^{24}.3^{14}-2.3.2^{24}.3^{15}}\)
\(=\frac{5.2^{24}.3^{15}-3^{15}.2^{26}}{19.2^{24}.3^{14}-2^{25}.3^{16}}\)
\(=\frac{2^{24}.3^{15}.\left(5-2^2\right)}{2^{24}.3^{14}.\left(19-3^2\right)}\)
\(=\frac{3.1}{10}\)
\(=\frac{3}{10}\)
\(\frac{15.4^{12}.9^7-4.3^{15}.8^8}{19.2^{24}.3^{14}-6.4^{12}.27^5}\)=\(\frac{3.5.2^{24}.3^{14}-2^2.3^{15}.2^{24}}{19.2^{24}.3^{14}-2.3.2^{24}.3^{15}}\)=\(\frac{3^{15}.5.2^{24}-2^{26}.3^{15}}{19.2^{24}.3^{14}-2^{25}.3^{16}}\)=\(\frac{3^{15}.2^{24}\left(5-4\right)}{2^{24}.3^{14}\left(19-2.4\right)}\)
=\(\frac{3.1}{19-8}=\frac{3}{11}\)
mk nhầm, pk là 3^2 ko pk là 2^2 đâu nhé, kết quả sẽ cho ra là \(\frac{3}{10}\)
