Question

\(\frac{15+25+35+...+105+115+125}{14.11+14.19}\)

Answer 1

\(=\frac{\left(15+125\right).12:2}{14.11+14.19}\)

\(=\frac{840}{14.30}\)

\(=\frac{14.30.2}{14.30}\)

\(=2\)

Answer 2

\(\frac{15+25+35+...+125}{14.11+14.19}\)= \(\frac{\left(125+15\right).\left(\left(125-15\right):10+1\right):2}{14\left(11+19\right)}\)= \(\frac{140.12:2}{14.20}\)= \(\frac{840}{280}\)= 3