Question

\(\frac{1}{2}x+\frac{2}{3}\left(x-1\right)=\frac{1}{3}\)

Answer 1

 \(\frac{1}{2}x+\frac{2}{3}x-\frac{2}{3}=\frac{1}{3}\)

\(\left(\frac{1}{2}+\frac{2}{3}\right)x=\frac{1}{3}+\frac{2}{3}\)

\(\left(\frac{3}{6}+\frac{4}{6}\right)x=1\)

\(\frac{7}{6}x=1\)

\(x=1:\frac{7}{6}=1.\frac{6}{7}\)

\(x=\frac{6}{7}\)

Answer 2

\(\frac{1}{2}x+\left(\frac{2}{3}x-\frac{2}{3}\right)=\frac{1}{3}\Rightarrow\left(\frac{1}{2}+\frac{2}{3}\right)x=1\Rightarrow\frac{7}{6}x=1\Rightarrow x=\frac{6}{7}\)

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