\(\frac{1}{2}.\frac{2}{3}.\frac{3}{4}.....\frac{2001}{2002}.\frac{2002}{2003}=\frac{1.2.3.....2001.2002}{2.3.4.....2002.2003}=\frac{1}{2003}\)
sai đề rồi ạn ơi ai cùng chung ý nghĩ thì tick
\(\frac{1}{2}\cdot\frac{2}{3}\cdot\frac{3}{4}\cdot\frac{4}{5}\cdot...\cdot\frac{99}{100}\)
Tính nhanh:\(\frac{2}{3}\cdot\frac{3}{4}\cdot\frac{4}{5}\cdot\frac{5}{6}:\frac{2}{6}+2019\)
tính bằng cách thuận tiện nhất
a,\(\frac{6}{7}\cdot\frac{16}{15}\cdot\frac{7}{6}\cdot\frac{21}{32}\)b, \(\frac{21}{17}\cdot\frac{13}{14}\cdot56\cdot\frac{3}{42}\) c,\(\frac{7}{4}\cdot\frac{11}{21}+\frac{11}{21}\cdot\frac{5}{4}\) d,\(\frac{23}{14}\cdot\frac{6}{14}-\frac{9}{14}\cdot\frac{6}{13}\)
Tính nhanh \(\left(1-\frac{1}{2}\right)\cdot\left(1-\frac{1}{3}\right)\cdot\left(1-\frac{1}{4}\right)\cdot\left(1-\frac{1}{5}\right)\)
tính
a)\(\frac{5}{6}\cdot\frac{3}{4}:2\)
b) \(\frac{2}{5}\cdot\frac{4}{7}:2\)
\(\frac{8}{5}\cdot\frac{4}{6}+\frac{24}{5}\cdot\frac{7}{6}+\frac{4}{5}\cdot\frac{11}{6}\cdot2\)
Tính bằng 2 cách
a. \(\frac{5}{24}\cdot\frac{5}{12}\cdot24\)
b. \(\frac{3}{7}\cdot\frac{16}{33}+\frac{16}{33}\cdot\frac{4}{7}\)
Ai nhanh ai đúng em click nèeee
Giúp em điiiii
\(\frac{7}{8}+\frac{\left(\frac{3}{4}-\frac{1}{2}\cdot\frac{2}{3}\right)}{\frac{4}{5}}\)
\(\frac{7}{8}-\left(\frac{1}{2}\cdot x-\frac{2}{3}\right)=\frac{3}{4}\)
