Sửa đề :
\(\frac{12}{3\cdot5}+\frac{12}{5\cdot7}+\frac{12}{7\cdot9}+...+\frac{12}{97\cdot99}\)
\(=\frac{1}{2}\left(\frac{12}{3}-\frac{12}{5}+\frac{12}{5}-\frac{12}{7}+\frac{12}{7}-\frac{12}{9}+...+\frac{12}{97}-\frac{12}{99}\right)\)
\(=\frac{1}{2}\left(\frac{12}{3}-\frac{12}{99}\right)\)
\(=\frac{1}{2}\cdot\frac{128}{33}\)
\(=\frac{64}{33}\)