\(\frac{0,4-\frac{2}{7}+\frac{2}{11}}{0,6-\frac{3}{7}+\frac{3}{11}}=\frac{2\left(0,2-\frac{1}{7}+\frac{1}{11}\right)}{3\left(0,2-\frac{1}{7}+\frac{1}{11}\right)}=\frac{2}{3}\)
\(\frac{0,4-\frac{2}{7}+\frac{2}{11}}{0,6-\frac{3}{7}+\frac{3}{11}}\)
\(=\frac{\frac{2}{5}-\frac{2}{7}+\frac{2}{11}}{\frac{3}{5}-\frac{3}{7}+\frac{3}{11}}\)
\(=\frac{2.\left(\frac{1}{5}-\frac{1}{7}+\frac{1}{11}\right)}{3.\left(\frac{1}{5}-\frac{1}{7}+\frac{1}{11}\right)}\)
\(=\frac{2}{3}\)
\(\frac{0,4-\frac{2}{7}+\frac{2}{11}}{0,6-\frac{3}{7}+\frac{3}{11}}=\frac{\frac{4}{10}-\frac{2}{7}+\frac{2}{11}}{\frac{6}{10}-\frac{3}{7}+\frac{3}{11}}=\frac{2}{3}\)