D n là số chính phương nên: \(n=k^2\left(k\in N\right)\)
Với k = 0 thì n = 0, \(n^3+2n^2+2n+4=4\)(thõa)
Với \(k\ge1\)thì ta có
\(\left(k^3+k+1\right)^2\ge k^6+2k^4+2k^2+4>\left(k^3+k\right)^2\)
Vì \(k^6+2k^4+2k^2+4\)là số chính phương nên
\(\left(k^3+k+1\right)^2=k^6+2k^4+2k^2+4\)
\(\Leftrightarrow k=1\)
\(\Rightarrow n=1\)
Vậy n = 0 hoặc n = 1
Find n such that A= n^3-2n^2+2n-4 is a prime number?
Find n such that A= n^3-2n^2+2n-4 is a prime number?
let m and n bel positive integers such that the fraction m/n is irreducible and the fraction 4m+3n/5m+2n is not irreducible. Find the greatest common divisor of 4m+3n and 5m+2n
1.Find the greatest negative integer value for n so that:
n4 - 25n2 - 70n - 49
2.Toán tiếng anh: If the length of a leg of a right angle is 11 and the lengths of the other two side are both positive integers, then the perimeter of a triangle is.............
Tìm số nguyên n sao cho
a) (2n^3 + n^2 + 7n + 1) chia hết cho 2n-1
b)(n^3 - 2) chia hết cho n-2
c)(n^3 - 3n^2 - 3n -1) chia hết cho n^2 + n + 1
d)((n^4 - 2n^3 = 2n^2 - 2n + 1) chia hết cho n^4 - 1
e)(n^3 - n^2 + 2n + 7) chia hết cho n^2 + 1
2) Tìm x thuộc Z , để:
a) \(n^2+2n-4⋮11\)
b)\(n^4-2n^3+2n^2-2n+1⋮n^4+1\)
c)\(n^3-n^2+2n+7⋮n^2+1\)
Tìm stn n sao cho :
a, (a^4-2n^3+2n^2-2n+1) chi hết cho (n^4-1)
b, (n^3-n^2+2n+7) chia hết cho (n^2+1)
Tìm số nguyên n sao cho:
a, n2 + 2n - 4 chia hết cho 11
b, 2n3 + n2 + 7n +1 chia hết cho 2n - 1
c, n3 - 2 chia hết cho n - 2
d, n3 - 3n2 - 3n - 1 chia hết cho n2 + n + 1
e, n4 - 2n3 + 2n2 - 2n + 1 chia hết cho n4 - 1
The sum of 2018 and a 3-digit number is a square number. Find the smallest possible value of the 3- digit numbers
