Question

Đưa biểu thức A sau về dạng không chứa dấu giá trị tuyệt đối 

A=\(|2x+1|+|x-1|-|x-2|\)

Answer 1

\(A=|2x+1|+|x-1|-|x-2|\)

Khi \(x< \frac{-1}{2}\) thì \(|2x+1|=-1-2x;|x-1|=1-x;|x-2|=2-x\)

\(\Rightarrow A=-2x-1+1-x+x-2\)

\(A=-2x-2\)

Khi \(\frac{-1}{2}\le x\le1\) thì \(|2x+1|=2x+1;|x-1|=1-x;|x-2|=2-x\)

\(\Rightarrow A=2x+1+1-x+x-2\)

\(A=2x\)

Khi \(1< x< 2\) thì \(|2x+1|=2x+1;|x-1|=x-1;|x-2|=2-x\)

\(\Rightarrow A=2x+1+x-1+x-2\)

\(A=4x-2\)

Khi \(x\ge2\) thì  \(|2x+1|=2x+1;|x-1|=x-1;|x-2|=x-2\)

\(\Rightarrow A=2x+1+x-1+2-x\)

\(A=2x+2\)

Answer 2

cảm ơn ạ