nS=\(\dfrac{3,2}{32}\)=0,1(mol)
.PTHH:S+O2 \(\underrightarrow{t^o}\)SO2
nS = nO2 =nSO2=0,1(mol)
mSO2=64.0,1=6,4(g)
PTHH : \(S+O_2->SO_2\) (1)
Ta có : \(n_S=\dfrac{m}{M}=\dfrac{3.2}{32}=0.1\left(mol\right)\)
Từ (1) => \(n_S=n_{SO_2}=0.1\left(mol\right)\)
=> \(m_{SO_2}=n.M=\) 0.1 x (32 + 16 x 2) = 0.1 x 64 = 6.4 (g)