Ta có : \(n_C:n_S=2:1->\dfrac{1}{2}n_c=n_S\)
Lại có : \(m_C+m_S=5,6\)
-> \(n_C.12+n_S.32=5,6\)
=> \(n_C.12+\dfrac{1}{2}n_C.32=5,6\)
=> \(n_C=0,2\left(mol\right)\)
-> \(n_S=\dfrac{1}{2}.0,2=0,1\left(mol\right)\)
PTHH : \(C+O_2\underrightarrow{t^o}CO_2\) (1)
\(S+O_2\underrightarrow{t^o}SO_2\) (2)
Từ (1) -> \(n_C=n_{O_2}=0,2\left(mol\right)\)
-> \(V_{O_2\left(1\right)}=0,2.22,4=4,48\left(l\right)\)
Từ (2) -> \(n_S=n_{O_2}=0,1\left(mol\right)\)
\(V_{O_2\left(2\right)}=0,1.22,4=2,24\left(l\right)\)
=> \(V=\dfrac{V_{O_2\left(1\right)}+V_{O_2\left(2\right)}}{20\%}=33,6\left(l\right)\)
Gọi \(\left\{{}\begin{matrix}n_{O2}:a\left(mol\right)\\n_{O3}:b\left(mol\right)\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}a+b=0,2\\\frac{32a+48b}{0,2}=20.2=40\end{matrix}\right.\)\(\Rightarrow\left\{{}\begin{matrix}a=0,1\\b=0,1\end{matrix}\right.\)
\(\left\{{}\begin{matrix}n_C:x\left(mol\right)\\n_S:y\left(mol\right)\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}12x+32y=5,6\\4x+4y=0,1.4+0,1.6=1\left(BT.e\right)\end{matrix}\right.\)\(\Rightarrow\left\{{}\begin{matrix}a=0,12\\b=0,13\end{matrix}\right.\)
\(\Rightarrow\frac{n_C}{n_S}=\frac{12}{13}\)
Đặt 12a, 13b là mol C,S trong 3,36g X
\(\Rightarrow12.12a+32.13a=3,36\)
\(\Rightarrow a=0,006\)
\(\left\{{}\begin{matrix}n_C=0,072\left(mol\right)\\n_S=0,078\left(mol\right)\end{matrix}\right.\underrightarrow{^{t^o}}\left\{{}\begin{matrix}CO_2=0,072\left(mol\right)\\SO_2=0,078\left(mol\right)\end{matrix}\right.\)
\(\Rightarrow\Sigma n_{khi}=0,15\left(mol\right)\)
\(n_{OH}=n_{NaOH}+n_{KOH}=0,2\left(mol\right)\)
\(\frac{n_{OH}}{n_{khi}}=1,3\Rightarrow\) Tạo 2 loại muối
Gọi chung CO2, SO2 là XO2 :\(\left\{{}\begin{matrix}n_{XO2}=0,15\left(mol\right)\\m_{XO2}=8,16\left(g\right)\end{matrix}\right.\)
\(\Rightarrow\overline{M_{XO2}}=\frac{8,16}{0,15}=54,4\)
\(\Rightarrow\overline{M_X}=22,4\)
Gọi chung NaOH ,KOH là ROH : \(\left\{{}\begin{matrix}n_{ROH}=0,25\left(mol\right)\\n_{ROH}=8,8\left(g\right)\end{matrix}\right.\)
\(\Rightarrow\overline{M_{ROH}}=\frac{8,8}{0,25}=35,2\)
\(\Rightarrow\overline{M_R}=18,2\)
\(ROH+XO_2\rightarrow RHXO_3\)
a________a_________a
\(2ROH+XO_2\rightarrow R_2XO_3+H_2O\)
2b________b_____b____________
\(\Rightarrow\left\{{}\begin{matrix}a+2b=0,25\\a+b=0,15\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}a=0,05\\b=0,1\end{matrix}\right.\)
\(\Rightarrow m=m_{RHXO3}+m_{R2XO3}=15,16\left(g\right)\)
