\(n_{C_2H_5OH}=\dfrac{11.5}{46}=0.25\left(mol\right)\)
\(C_2H_5OH+3O_2\underrightarrow{^{t^0}}2CO_2+3H_2O\)
\(0.25............0.75....0.5............0.75\)
\(V_{CO_2}=0.5\cdot22.4=11.2\left(l\right)\)
\(m_{H_2O}=0.75\cdot18=13.5\left(g\right)\)
\(V_{O_2}=0.75\cdot22.4=16.8\left(l\right)\)
\(V_{kk}=5V_{O_2}=5\cdot16.8=84\left(l\right)\)