\(0,3\left(18\right)=0,3+0,0\left(18\right)=\frac{1}{10}+0,\left(18\right).0,1=\frac{1}{10}+\frac{18}{99}.\frac{1}{10}=\frac{1}{10}+\frac{18}{990}=\frac{13}{110}\)
ta có \(0,3\left(18\right)=\frac{1}{10}\times3,\left(18\right)=\frac{1}{10}\left(3+0,\left(18\right)\right)=\frac{1}{10}\left(3+\frac{1}{99}.18\right)=\frac{1}{10}\left(3+\frac{2}{11}\right)=\frac{1}{10}\times\frac{35}{11}=\frac{7}{22}\)
Vậy 0,3(18)=\(\frac{7}{22}\)