Có : G - T = 140 nu
2T + 3G = 2520
=> A = T = 420 nu
G = X = 560 nu
N = 2 ( A + G ) = 1960 nu
l = N x 3,4 : 2 = 3332Ao
Ta có: \(G-T=140\)
\(2T+3G=2520\)
\(\Rightarrow\left\{{}\begin{matrix}A=T=420nu\\G=X=560nu\end{matrix}\right.\)
\(N=2A+2G=2\cdot420+2\cdot560=1960nu\)
\(l=\dfrac{2N}{3,4}=\dfrac{2\cdot1960}{3,4}=1152,94A^o\)