\(A=\frac{10^8-1+3}{10^8-1}=1+\frac{3}{10^8-1}\)
\(B=\frac{10^8-3+3}{10^8-3}=1+\frac{3}{10^8-3}\)
Vì \(\frac{3}{10^8-3}>\frac{3}{10^8-1}\) nên B>A
A = 10 ^ 8 = 10 x 10 x 10 x 10 x 10 x 10 x 10 x 10 +2/10^8 = 2/10 x 2/10 x 2/10 x 2/10 x 2/10 x 2/10 x 2/10 x 2/10 - 1
B = 10 ^ 8 = 10 x 10 x 10 x 10 x 10 x 10 x 10 x 10 - 3
A = 100000000 + 1/390625 =100000000 - 1 = 9999999
B = 100000000 - 3 = 9999997
So sánh : 9999997 < 9999999
cho nên A lớn hơn