Bài 1: 0,01m3 < 1,99m3
Bài 2: Tìm \(x\):
\(x\)x 4 + \(\frac{1}{2}\)x \(x\)= 55,35
\(x\)x (4 + \(\frac{1}{2}\)) = 55,35
\(x\)x \(\frac{9}{2}\)= 55,35
\(x\)= 55,35 : \(\frac{9}{2}\)
\(x\)= 249,075
1,
\(0,01m^3=\frac{1}{100}m^3\); vậy \(\frac{1}{100}m^3< \frac{1}{99}m^3\)
2, Lời giải
\(x\cdot4+\frac{1}{2}\cdot x=55,35\)
\(\Rightarrow x\cdot\left(4+\frac{1}{2}\right)=55,35\)
\(\Rightarrow x\cdot4\frac{1}{2}=55.35\)
\(\Rightarrow x\cdot4,5=55,35\)
\(x=55,35:4,5\)
\(x=12,3\)
thanks for answering!!!!!!!!!!!!!!!!!
