\(\Rightarrow x^2=16\Rightarrow\left[{}\begin{matrix}x=4\\x=-4\end{matrix}\right.\)
\(\dfrac{x}{2}=\dfrac{8}{x}\Rightarrow x^2=8.2\)
\(\Rightarrow x^2=16\)
\(\Rightarrow\left[{}\begin{matrix}x=-4\\x=4\end{matrix}\right.\)
\(\Rightarrow x^2=16\Rightarrow\left[{}\begin{matrix}x=4\\x=-4\end{matrix}\right.\)
\(\dfrac{x}{2}=\dfrac{8}{x}\Rightarrow x^2=8.2\)
\(\Rightarrow x^2=16\)
\(\Rightarrow\left[{}\begin{matrix}x=-4\\x=4\end{matrix}\right.\)
Tìm x
\(a,3-x=x+1,8\)
\(b,2x-5=7x+35\)
\(c,2\left(x+10\right)=3\left(x-6\right)\)
\(d,8\left(x-\dfrac{3}{8}\right)+1=6\left(\dfrac{1}{6}+x\right)+x\)
\(e,\dfrac{2}{9}-3x=\dfrac{4}{3}-x\)
\(g,\dfrac{1}{2}x+\dfrac{5}{6}=\dfrac{3}{4}x-\dfrac{1}{2}\)
\(h,x-4=\dfrac{5}{6}\left(6-\dfrac{6}{5}x\right)\)
\(k,7x^2-11=6x^2-2\)
\(m,5\left(x+3.2^3\right)=10^2\)
\(n,\dfrac{4}{9}-(\dfrac{1}{6^2})=\dfrac{2}{3}\left(x-\dfrac{2}{3}\right)^2+\dfrac{5}{12}\)
2. Tìm x biết:
a)\(\dfrac{2}{\left(x+2\right)\left(x+4\right)}\) + \(\dfrac{4}{\left(x+4\right)\left(x+8\right)}\) + \(\dfrac{6}{\left(x+8\right)\left(x+14\right)}\) = \(\dfrac{x}{\left(x+2\right)\left(x+14\right)}\).
b)\(\dfrac{x}{2023}\) + \(\dfrac{x+1}{2022}\) + \(\dfrac{x+2}{2021}\) +...+ \(\dfrac{x+2022}{1}\) + 2023 = 0.
Gíup mình giải 2 bài này với!
Cảm ơn các bạn rất nhiều!!!
Tìm x, biết:
a) \(\dfrac{-1}{10}\) + \(\dfrac{2}{5}\)x + \(\dfrac{7}{20}\) = \(\dfrac{1}{10}\)
b) \(\dfrac{1}{3}\) + \(\dfrac{1}{2}\) : x= \(-\dfrac{1}{5}\)
c) \(-\dfrac{2}{3}\) : x + \(\dfrac{5}{8}\) = \(-\dfrac{7}{12}\)
tìm x biết
a) \(\dfrac{x}{2}\)=\(\dfrac{y}{5}\) và x+y=-14
b)\(\dfrac{x}{7}=\dfrac{y}{5}\) và x-y=8
Tìm x: \(\dfrac{1}{2}-\dfrac{1}{4}+\dfrac{1}{8}-\dfrac{1}{16} +...-\dfrac{1}{1024}=\dfrac{x}{1024}\)
Tìm x
\(\dfrac{3}{4}x+\dfrac{-1}{2}=\dfrac{-13}{8}\)
\(\left|x\right|+0,25=1,75.3\)
\(\dfrac{2x-1}{3}=\dfrac{-5}{0,6}\)
tìm x biết
| \(2\dfrac{1}{5}\)-x|+|x-\(\dfrac{1}{5}\)|+8\(\dfrac{1}{5}\) =1,2
tìm x trong các tỉ lệ thức sau:
\(\dfrac{4}{x}=\dfrac{8}{x+1}\)
\(\dfrac{3}{2}=\dfrac{9}{\left|x\right|}\)
\(\dfrac{15}{2x-1}=\dfrac{5}{3}\)
heeelp
Tìm x, biết \(\dfrac{1}{4}.\dfrac{2}{6}.\dfrac{3}{8}.\dfrac{4}{10}.\dfrac{5}{12}...\dfrac{30}{62}.\dfrac{31}{64}=2^x\)