Question

\(\dfrac{x}{2}-\left(\dfrac{3x}{5}-\dfrac{13}{5}\right)=\left(\dfrac{7}{5}+\dfrac{7}{10}.x\right)\)

Answer 1

`x/2-([3x]/5-13/5)=7/5+7/10x`

`=>1/2x-3/5x+13/5=7/5+7/10x`

`=>1/2x-3/5x-7/10x=7/5-13/5`

`=>-4/5x=-6/5`

`=>x=3/2`

Answer 2

=\(\dfrac{x}{2}\)-\(\dfrac{3x}{5}\)-\(\dfrac{13}{5}\)=\(\dfrac{-7}{5}\)-\(\dfrac{7x}{10}\)

=\(\dfrac{1}{2}x\)-\(\dfrac{3}{5}x\)+\(\dfrac{7}{10}x\)=\(\dfrac{6}{5}\)

=\(\dfrac{3}{5}x\)=\(\dfrac{6}{5}\)

=\(x\)=-2