\(\Rightarrow7\left(x+1\right)=4\left(x-5\right)\left(x\ne5\right)\\ \Rightarrow7x+7=4x-20\\ \Rightarrow3x=27\Rightarrow x=9\left(tm\right)\)
ĐK: x khác 5
\(\dfrac{x+1}{x-5}=\dfrac{4}{7}\\ =>7\left(x+1\right)=4\left(x-5\right)\\ < =>7x+7=4x-20\\ < =>3x=-27\\ < =>x=-9\left(tm\right)\)