\(\dfrac{x+11}{14-x}=\dfrac{2}{3}\)
\(\Rightarrow3\left(x+11\right)=2\left(14-x\right)\)
\(\Rightarrow3x+33=28-2x\)
\(\Rightarrow5x=-5\Rightarrow x=-1\)
(14 - x)2 = (x + 11)3
28 - 2x = 3x + 33
28 - 2x - 3x - 33 = 0
- 5 - 5x = 0
x = -1
\(\dfrac{x+11}{14-x}=\dfrac{2}{3}\\ \Leftrightarrow3\left(x+11\right)=2\left(14-x\right)\\ \Leftrightarrow3x+33=28-2x\\ \Leftrightarrow3x+2x=28-33\\ \Leftrightarrow5x=-5\Leftrightarrow x=-1\\ Vậyx=-1\)