\(\dfrac{9}{10}+\dfrac{3}{4}=\dfrac{18}{20}+\dfrac{15}{20}=\dfrac{33}{20}\)
\(\dfrac{9}{10}+\dfrac{3}{4}=\dfrac{18}{20}+\dfrac{15}{20}=\dfrac{33}{20}\)
bài 1:
2 : y x \(\dfrac{3}{5}\) = \(\dfrac{9}{10}\) \(\dfrac{5}{4}-\dfrac{2}{5}:\) y = 1 \(\dfrac{3}{4}x\) (\(\dfrac{7}{2}\) - y) =\(\dfrac{3}{2}\)
\(\dfrac{4}{3}\) x \(\dfrac{9}{5}\) - \(\dfrac{3}{10}\)
Giúp mình nhé!
Bài 2 Tìm y
a) \(\dfrac{1}{2}-2xy=\dfrac{9}{20}\) b)\(\dfrac{3}{5}:\dfrac{4}{3}:y=2+\dfrac{7}{10}\) c) y + y x\(\dfrac{3}{2}-y\) x \(\dfrac{1}{2}=\dfrac{1}{10}\)
Tính bằng cách thuận tiện nhất
a, \(\dfrac{1}{10}+\dfrac{2}{10}+\dfrac{3}{10}+\dfrac{4}{10}+\dfrac{5}{10}+\dfrac{6}{10}+\dfrac{7}{10}+\dfrac{8}{10}+\dfrac{9}{10}\)
b, 13,25 : 0,5 + 13,25 : 0,25 + 13,25 : 0,125 + 13,25 x 6
Giúp mình với mình đang gấp
mọi người giúp mình câu: \(\dfrac{8}{10}+\dfrac{3}{5}x1\dfrac{1}{9}:\dfrac{4}{55}\)
\(\dfrac{4}{9}+\dfrac{5}{8}\)=
\(\dfrac{6}{10}+\dfrac{9}{2}=\)
\(\dfrac{10}{2}-\dfrac{5}{2}=\)
\(\dfrac{8}{8}x1=\)
a) \(\dfrac{3}{7}\)+\(\dfrac{4}{9}\)+\(\dfrac{8}{14}\)+\(\dfrac{10}{18}\)
b) \(\dfrac{1}{2}\)x\(\dfrac{2}{3}\):\(\dfrac{5}{6}\)x\(\dfrac{5}{6}\)
bài này là bài tính bằng cách thuận tiện nhất nha !
Bài 1:
\(a,\dfrac{1}{5}+\dfrac{1}{10}+\dfrac{1}{20}+\dfrac{1}{40}+...............+\dfrac{1}{1280}\)
\(b,\dfrac{1}{3}+\dfrac{1}{9}+\dfrac{1}{27}+\dfrac{1}{81}+..............+\dfrac{1}{59049}\)
\(c,\dfrac{1}{2}\times3+\dfrac{1}{3}\times4+\dfrac{1}{4}\times5+\dfrac{1}{5}\times6\)
a)\(\dfrac{7}{8}\)x\(\dfrac{3}{13}\)+\(\dfrac{4}{9}\)x\(\dfrac{4}{13}\)
b)\(\dfrac{6}{5}\)+\(\dfrac{7}{3}\)+\(\dfrac{8}{9}\)
c)23: \(\dfrac{5}{14}\)+\(\dfrac{6}{7}\)+\(\dfrac{4}{9}\)
d)\(4\dfrac{1}{4}\)+\(7\dfrac{3}{7}\)-\(2\dfrac{4}{17}\)
e)8-(9\(\dfrac{2}{11}\)+\(\dfrac{8}{33}\))