\(\Leftrightarrow-\dfrac{1}{7}:\left(\dfrac{x}{3}-2\right)=-1-\dfrac{8}{7}=-\dfrac{15}{7}\\ \Leftrightarrow\dfrac{x}{3}-2=\dfrac{1}{15}\\ \Leftrightarrow\dfrac{x}{3}=\dfrac{1}{15}+2=\dfrac{31}{15}\\ \Leftrightarrow x=\dfrac{31.3}{15}=\dfrac{31}{5}\)
`#3107.101107`
`8/7 - 1/7 \div (x/3 - 2) = -1`
`=> 1/7 \div (x/3 - 2) = 8/7 - (-1)`
`=> 1/7 \div (x/3 - 2) = 8/7 + 1`
`=> 1/7 \div (x/3 - 2) = 15/7`
`=>. x/3 - 2 = 1/7 \div 15/7`
`=> x/3 - 2 = 1/15`
`=> x/3 = 1/15 + 2`
`=> x/3 = 31/15`
`=> 15x = 93 => x = 6,2`
Vậy, `x = 6,2.`
\(\dfrac{8}{7}-\dfrac{1}{7}:\left(\dfrac{x}{3}-2\right)=-1\\ \Rightarrow\dfrac{1}{7}:\left(\dfrac{x}{3}-2\right)=\dfrac{8}{7}+1\\ \Rightarrow\dfrac{1}{7}:\left(\dfrac{x}{3}-2\right)=\dfrac{15}{7}\\ \Rightarrow\dfrac{x}{3}-2=\dfrac{1}{7}:\dfrac{15}{7}\\ \Rightarrow\dfrac{x}{3}-2=\dfrac{1}{15}\\ \Rightarrow\dfrac{x}{3}=\dfrac{1}{15}+2\\ \Rightarrow\dfrac{x}{3}=\dfrac{31}{15}\\ \Rightarrow15x=31.3\\ \Rightarrow15x=93\\ \Rightarrow x=\dfrac{93}{15}\)
