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https://hoc24.vn/cau-hoi/hep-mecho-dfracabdfraccd-chung-minhdfrac7a23ab11a2-8b2dfrac7c23cd11c2-8d2.1358224776256
\(Cho\)\(\dfrac{a}{b}\)
\(Chứng\) \(Minh\)
\(\dfrac{7a^2+3ab}{11a^2-8b}\)\(=\)\(\dfrac{7c^2+3cd}{11c^2-8d}\)
Hẹp me
Cho \(\dfrac{a}{b}=\dfrac{c}{d}\) Chứng minh:
\(\dfrac{7a^2+3ab}{11a^2-8b^2}=\dfrac{7c^2+3cd}{11c^2-8d^2}\)
cho \(\dfrac{a}{b}=\dfrac{c}{d}\) Chứng minh rằng
\(\dfrac{7a^2+3ab}{11a^2+8b^2}=\dfrac{7c^2+3cd}{11c^2-8d^2}\)
Cho a/b = c/d với a, b, c, d > 0. Chứng minh rằng\(\dfrac{7a^2+3ab}{11a^2-8b^2}=\dfrac{7c^2+3cd}{11c^2-8d^2}\)
Cho tỉ lệ thức\(\dfrac{a}{b}\)=\(\dfrac{c}{d}\). Chứng minh rằng ta có tỉ lệ sau: \(\dfrac{7a^2+3ab}{11a^2-8b^2}\)=\(\dfrac{7c^2+3cd}{11c^2-8d^2}\)
cho tỉ lệ thức \(\dfrac{a}{b}=\dfrac{c}{d}\)(b\(\ne\)0;d\(\ne\)0)
e)\(\dfrac{2014a-2015b}{2016a+2017b}=\dfrac{2014c-2015d}{2016c+2017d}\)
f)\(\dfrac{7a^2+3ab}{11a^2-8b^2}=\dfrac{7c^2+3cd}{11c^2-8d^2}\)
chung minh rang 7a^2 + 3ab / 11a^2 -8b^2 = 7c^2 + 3cd / 11c^2 - 8d^2
cho a/b=c/d ,cminh rằng
(7a^2+3ab)/(11a^2-8b^2)=(7c^2+3cd)/(11c^2-8d^2)
CMR:nếu a/b=c/d thì a)5a+3b/5a-3b ; b)7a^2+3ab/11a^2-8b^2=7c^2+3cd/11c^2-8d^2
