\(=\dfrac{-7}{24}+\dfrac{-10}{24}=\dfrac{-\left(7+10\right)}{24}=\dfrac{-17}{24}\)
\(\dfrac{7}{-24}+\dfrac{-5}{12}=\dfrac{-7}{24}+\dfrac{-10}{24}=\dfrac{\left(-7\right)+\left(-10\right)}{24}=\dfrac{-17}{24}\)
Lời giải:
$\frac{7}{-24}+\frac{-5}{12}=\frac{-7}{24}+\frac{-10}{24}=\frac{-7+(-10)}{24}=\frac{-17}{24}$
EZ
\(\dfrac{7}{-14}+\dfrac{-5}{12}=\dfrac{-7}{24}+\dfrac{-10}{24}=\dfrac{-17}{24}\)