`6/5 + 3/5 + ... =2`
`=> 2- 6/5 -3/5= 10/5 - 6/5 -3/5=1/5`
Mà `1/5=2/10`
`->B`
` 6/5+3/5+...=2`
`9/5+...=2`
`2-9/5=...`
`10/5-9/5=1/5`
`1/5=2/10`
=> Chọn đáp án `B`
Ta có: \(\dfrac{6}{5}+\dfrac{3}{5}+...=2\)
\(\dfrac{9}{5}+...=2\)
\(...=2-\dfrac{9}{5}\)
\(...=\dfrac{10}{5}-\dfrac{9}{5}\)
\(...=\dfrac{1}{5}\)
Mà \(\dfrac{1}{5}=\dfrac{2}{10}\)
`->` Đáp án B.