5/6+7/8=41/24 5/8-2/5=9/40 9/10x5/6=3/4 6/5:3/7=42/15
https://hoc24.vn/cau-hoi/dfrac56dfrac78dfrac-dfrac58-dfrac25-dfrac910xdfrac56dfrac65dfrac37.7107801859512
=> bn tham khảo đây nha
\(\dfrac{1}{3}+\dfrac{2}{3}=\)
\(\dfrac{4}{5}+\dfrac{5}{6}=\)
\(\dfrac{4}{5}-\dfrac{3}{5}=\)
\(\dfrac{9}{8}-\dfrac{4}{2}=\)
\(\dfrac{8}{5}x\dfrac{5}{8}=\)
\(\dfrac{6}{7}x\dfrac{4}{7}=\)
\(\dfrac{4}{5}:\dfrac{4}{5}=\)
\(\dfrac{5}{5}:\dfrac{5}{5}=\)
a,
a)\(\dfrac{7}{8}\)x\(\dfrac{3}{13}\)+\(\dfrac{4}{9}\)x\(\dfrac{4}{13}\)
b)\(\dfrac{6}{5}\)+\(\dfrac{7}{3}\)+\(\dfrac{8}{9}\)
c)23: \(\dfrac{5}{14}\)+\(\dfrac{6}{7}\)+\(\dfrac{4}{9}\)
d)\(4\dfrac{1}{4}\)+\(7\dfrac{3}{7}\)-\(2\dfrac{4}{17}\)
e)8-(9\(\dfrac{2}{11}\)+\(\dfrac{8}{33}\))
Bài 2: (Đề1) Tính
\(4\dfrac{2}{3}+3\dfrac{2}{7}\)=..........................
\(8\dfrac{5}{9}:5\dfrac{1}{2}\) =..........................
\(6\dfrac{5}{7}:2\dfrac{1}{6}\) =..........................
\(1\dfrac{3}{4}x2\dfrac{5}{6}\) =..........................
\(5\dfrac{3}{4}-2\) =..........................
\(a,\dfrac{1}{3}và\dfrac{2}{5}\) \(b,\dfrac{3}{7}và\dfrac{8}{9}\) \(c,\dfrac{3}{5}và\dfrac{7}{10}\) \(d,\dfrac{1}{3}và\dfrac{5}{6}\)
a) \(\dfrac{3}{7}\)+\(\dfrac{4}{9}\)+\(\dfrac{8}{14}\)+\(\dfrac{10}{18}\)
b) \(\dfrac{1}{2}\)x\(\dfrac{2}{3}\):\(\dfrac{5}{6}\)x\(\dfrac{5}{6}\)
bài này là bài tính bằng cách thuận tiện nhất nha !
a,\(\dfrac{1}{7}\text{x}\dfrac{2}{7}+\dfrac{1}{7}\text{x}\dfrac{5}{7}+\dfrac{6}{7}\) b,\(\dfrac{6}{11}\text{x}\dfrac{4}{9}+\dfrac{6}{11}\text{x}\dfrac{7}{9}-\dfrac{6}{11}\text{x}\dfrac{2}{9}\)
c, \(\dfrac{4}{25}\text{x}\dfrac{5}{8}\text{x}\dfrac{25}{4}\text{x}24\)
Tính :
\(A.\dfrac{25}{7}-2+\dfrac{3}{2}\)
\(B.\dfrac{4}{5}x\dfrac{10}{3}:8\)
\(C.\dfrac{7}{3}+\dfrac{2}{5}:\dfrac{1}{6}\)
\(\dfrac{15}{14}\) : \(\dfrac{10}{21}\) x \(\dfrac{1}{5}\)
\(5\) x \(\dfrac{1}{5}\) + \(\dfrac{1}{5}\)
\(7\) : \(\dfrac{1}{5}\) - \(\dfrac{1}{5}\)
\(6\) + \(\dfrac{1}{5}\) : \(2\)
\(8\) - \(\dfrac{1}{5}\) x \(7\)
so sánh các hỗn số sau:
\(7\dfrac{4}{5}\) và \(9\dfrac{1}{2}\)
\(7\dfrac{1}{6}\) và \(3\dfrac{4}{5}\)
\(9\dfrac{9}{1}\) và \(5\dfrac{8}{6}\)
Tính giá trị biểu thức:
(\(\dfrac{6}{11}+\dfrac{5}{11}\)) x \(\dfrac{3}{7}\) \(\dfrac{3}{5}x\dfrac{7}{9}-\dfrac{3}{5}x\dfrac{2}{9}\) \(\left(\dfrac{6}{7}-\dfrac{4}{7}\right):\dfrac{2}{5}\)
