Lời giải:
Gọi biểu thức trên là $A$
\(A=\frac{2^{20}.3^{12}+3^{12}.2^{15}}{2^{13}.3^{13}.2^2+2^{16}.3^{12}}=\frac{2^{20}.3^{12}+3^{12}.2^{15}}{2^{15}.3^{13}+2^{16}.3^{12}}\)
\(=\frac{2^{15}.3^{12}(2^5+1)}{2^{15}.3^{12}(3+2)}=\frac{2^5+1}{5}=\frac{33}{5}\)