`3 / [ x + 5 ] = 15%`
`3 / [ x + 5 ] = 3 / 20`
`x + 5 = 20`
`x = 20 - 5`
`x = 15`
3/x+5 = 15%
= 100 . 3 = ( x + 5 ) . 15
300 = ( x + 5 ) . 15
300 = 15x + 75
15x + 75 = 300
15x = 300 - 75
15x = 225
x = 225 : 15
x = 15.
`3 / [ x + 5 ] = 15%`
`3 / [ x + 5 ] = 3 / 20`
`x + 5 = 20`
`x = 20 - 5`
`x = 15`
3/x+5 = 15%
= 100 . 3 = ( x + 5 ) . 15
300 = ( x + 5 ) . 15
300 = 15x + 75
15x + 75 = 300
15x = 300 - 75
15x = 225
x = 225 : 15
x = 15.
\(\dfrac{x}{15}=\dfrac{3}{5}-\dfrac{-2}{3}\) ok
\(\Rightarrow\dfrac{x}{15}=\dfrac{9}{15}+\dfrac{10}{15}\)
\(\Rightarrow\dfrac{x}{15}=\dfrac{19}{15}\)
\(\Rightarrow x=19\)
a,\(\dfrac{x}{-3}\text{=}\dfrac{-5}{15}\) b,\(\dfrac{1173}{x}\text{=}\dfrac{3}{5}\)
c,\(\dfrac{2}{x}\text{=}\dfrac{y}{15}\text{=}\dfrac{-25}{75}\)
B1: Tìm x:
1/ \(\dfrac{x+3}{15}\) = \(\dfrac{1}{3}\) - \(\dfrac{1}{15}\)
2/ (2x - 5) = (x - 3) = 0
3/ (3x - 4) - (2x - 5) = 3
4/ (2x + 1) x (\(\dfrac{1}{2}\)x - 1) = 0
Tìm x:
a) \(\dfrac{-3}{7}\).x=\(\dfrac{3}{56}\).\(\dfrac{28}{9}\)
b) x-\(\dfrac{3}{16}\)=\(\dfrac{7}{15}\):\(\dfrac{3}{5}\)
c) \(\dfrac{2}{5}\)+\(\dfrac{1}{5}\).x=\(\dfrac{5}{6}\)
d) \(\dfrac{3}{4}\)x-\(\dfrac{2}{5}\)x=\(\dfrac{3}{7}\).\(\dfrac{1}{6}\)+\(\dfrac{5}{7}\).\(\dfrac{1}{6}\)
*Lưu ý: Trình bày chi tiết kết quả.
tìm x biết
a , \(\dfrac{-3}{10}\)-(\(\dfrac{-1}{5}\) +x)=\(\dfrac{-3}{2}\)
b, -(-x+ \(\dfrac{3}{4}\))- \(\dfrac{12}{8}\).- \(\dfrac{32}{15}\)=- \(\dfrac{-1}{2}\)
c, \(\dfrac{x-3}{x+5}\)=\(\dfrac{4}{3}\)
\(\dfrac{2x-1}{12}=\dfrac{5}{3^{ }}\)
\(\dfrac{2x-3}{15}=\dfrac{3}{5}\)
Tìm x
Tìm x biết:
\(a,\dfrac{4}{5}+x=\dfrac{2}{3}\)
\(b,\dfrac{-5}{6}-x=\dfrac{2}{3}\)
\(c,\dfrac{1}{2}x+\dfrac{3}{4}=\dfrac{-3}{10}\)
\(d,\dfrac{x}{3}-\dfrac{1}{2}=\dfrac{1}{5}\)
\(e,\dfrac{x+3}{15}=\dfrac{1}{3}\)
\(h,x+30\%x=-1,3\)
\(k,3\dfrac{1}{3}x+16\dfrac{1}{4}=13,25\)
\(m,\dfrac{x-6}{2}=\dfrac{50}{x-6}\)
\(n,x-13,4=24,5-6,7.5,2\)
\(p,15,7x+3,6x=-96,5\)
\(q,2,5x-11,6=-59,1\)
Tìm x:
a) \(\dfrac{-x}{4}=\dfrac{-9}{x}\)
b) \(\dfrac{5}{9}+\dfrac{x}{-1}=\dfrac{-1}{3}\)
c) \(x:3\dfrac{1}{15}=1\dfrac{1}{2}\)
d) \(\dfrac{3x-1}{-5}=\dfrac{-5}{3x-1}\)
tìm x :
a, x . \(\dfrac{-5}{8}\) = \(\dfrac{15}{32}\) b, \(\dfrac{3}{10}\) : x =\(\dfrac{-9}{20}\)
c, \(\dfrac{-1}{4}\) x + \(\dfrac{4}{5}\) =\(\dfrac{3}{4}\) d, \(\dfrac{-7}{8}\) + \(\dfrac{2}{3}\) :x = \(\dfrac{3}{5}\) . \(\dfrac{-5}{12}\)
Tìm x biết:
a, \(\dfrac{3}{5}:x+\dfrac{1}{5}=\dfrac{11}{25}\)
b, \(2\left(x-\dfrac{1}{3}\right)-1\dfrac{2}{3}=\dfrac{-23}{15}\)
c, \(\left|x+1\right|-\dfrac{1}{7}=\dfrac{1}{3}\)
d, \(\dfrac{x+1}{3}=\dfrac{2x-1}{5}\)