`(3x+2)/3 <= (x-4)/7`
`<=>7(3x+2) <= 3(x-4)`
`<=> 21x+14<=3x-12`
`<=>18x <= -26`
`<=> x <=-13/9`
`(3x+2)/3 <= (x-4)/7`
`<=>7(3x+2) <= 3(x-4)`
`<=> 21x+14<=3x-12`
`<=>18x <= -26`
`<=> x <=-13/9`
\(\dfrac{3x+2}{3}\le\dfrac{x-4}{7}\) help em với mn ơi
\(\dfrac{2x-5}{3}=\dfrac{x+2}{2}\) help em vs mn ơi
\(\dfrac{x+1}{x-3}+\dfrac{x-1}{x+3}=\dfrac{x+6}{x^2-9}\) help em vs mn ơi
\(\dfrac{3-3x}{5}\)=\(\dfrac{x-1}{2}\) help em vs mn
\(\dfrac{3}{5}x^3y\left(10xy^3-\dfrac{5}{3}y^2+\dfrac{5}{6}xy\right)\) help em vs mn ơi
\(\dfrac{x}{x+4}+\dfrac{56-x^2}{x^2}=\dfrac{5}{x-4}\) help em vs mn oi
\(\dfrac{x-1}{2}-\dfrac{x-2}{3}\le\dfrac{x-3}{4}\)
mn cho xin đáp án vs ạ mình nhìn đáp án của mình nó cứ sai sai ạ
\(\dfrac{3x+4}{8}=\dfrac{3-7x}{6}\) giup em vs mn
Giải bất phương trình sau
a)\(\dfrac{2-x}{3}\)\(-x-2\le\dfrac{x-17}{2}\)
b) \(\dfrac{2x+1}{3}-\dfrac{x-4}{4}\le\dfrac{3x+1}{6}-\dfrac{x-4}{12}\)