`3/7 x -2/3 x =10/21`
`=> (3/7-2/3)x=10/21`
`=> ( 9/21 - 14/21)x=10/21`
`=>-5/21 x=10/21`
`=> x=10/21 : (-5/21)`
`=> x=10/21 xx (-21/5)`
`=>x=-2`
(3/7 - 2/3).x = 10/21
-5/21.x = 10/21
x = 10/21 : (-5/21)
x = -2
vậy x = -2
`3/7 x -2/3 x =10/21`
`=> (3/7-2/3)x=10/21`
`=> ( 9/21 - 14/21)x=10/21`
`=>-5/21 x=10/21`
`=> x=10/21 : (-5/21)`
`=> x=10/21 xx (-21/5)`
`=>x=-2`
(3/7 - 2/3).x = 10/21
-5/21.x = 10/21
x = 10/21 : (-5/21)
x = -2
vậy x = -2
Tìm x, biết:
a) \(\dfrac{3}{7}\)x - \(\dfrac{2}{3}\)x = \(\dfrac{10}{21}\)
b) \(\dfrac{7}{35}\) : (x - \(\dfrac{1}{3}\)) = \(-\dfrac{2}{25}\)
c) 3.(x - \(\dfrac{1}{2}\)) - 5. (x + \(\dfrac{3}{5}\)) = -x + \(\dfrac{1}{5}\)
Chọn câu trả lời đúng \(\left(2x+\dfrac{1}{5}\right)\left(-\dfrac{3}{5}x+\dfrac{4}{7}\right)=0\) thì:
A. x = \(\dfrac{-1}{10}\) hoặc x = \(\dfrac{20}{21}\)
B. x = \(\dfrac{20}{21}\)
C. x = \(-\dfrac{1}{10}\)
D. x = \(-\dfrac{20}{21}\)
a/ \(\dfrac{-3}{5}\) - x = \(\dfrac{21}{10}\)
b/ x : \(\dfrac{2}{9}\) = \(\dfrac{9}{2}\)
c/ \(\dfrac{x}{9}\) = \(\dfrac{5}{3}\)
d/ x : \(\left(\dfrac{2}{5}\right)^3\)= \(\left(\dfrac{5}{2}\right)^3\)
\(\dfrac{-3}{7}\) - \(\dfrac{2}{21}\) + (2\(\dfrac{2}{3}\) - 3\(\dfrac{1}{4}\)) = x - \(\dfrac{5}{3}\)
a/ \(\dfrac{-3}{5}\) - x = \(\dfrac{21}{10}\)
b/ x : \(\dfrac{2}{9}\) = \(\dfrac{9}{2}\)
c/ \(\dfrac{x}{9}\) = \(\dfrac{5}{3}\)
d/ x : \(\left(\dfrac{2}{5}\right)^3\)= \(\left(\dfrac{5}{2}\right)^3\)
giúp mik gấp nha, mik sắp thi rồi!
Tìm x, biết:
a) \(\dfrac{-1}{10}\) + \(\dfrac{2}{5}\)x + \(\dfrac{7}{20}\) = \(\dfrac{1}{10}\)
b) \(\dfrac{1}{3}\) + \(\dfrac{1}{2}\) : x= \(-\dfrac{1}{5}\)
c) \(-\dfrac{2}{3}\) : x + \(\dfrac{5}{8}\) = \(-\dfrac{7}{12}\)
a) \(\dfrac{2}{3}.x+\dfrac{5}{7}=\dfrac{3}{10}\)
b)\(\dfrac{3}{4}.x-\dfrac{1}{2}=\dfrac{3}{7}\)
GIÚP MÌNH VỚI
a, x - \(\dfrac{5}{7}\)=\(\dfrac{19}{21}\)
b,\(\dfrac{5}{3}\)-I x - \(\dfrac{1}{5}\)I = \(\dfrac{1}{3}\)
c, (x - \(\dfrac{2}{5}\)) = \(\dfrac{1}{4}\)
d, 5\(\sqrt{x}\) - 30 = 15
\(b,\dfrac{x}{2}-\left(\dfrac{3x}{5}-\dfrac{13}{5}\right)=-\left(\dfrac{7}{5}+\dfrac{7}{10}.x\right)\)
\(c,\dfrac{2x-3}{3}+\dfrac{-3}{2}=\dfrac{5-3x}{6}-\dfrac{1}{3}\)
\(d,\dfrac{2}{3x}-\dfrac{3}{12}=\dfrac{4}{5}-\left(\dfrac{7}{x}-2\right)\)
\(e,2\left(x-1\right)=\left(x-1\right)^2\)