Question

\(\dfrac{3}{5}\)  . \(x\) + \(\dfrac{1}{2}\) = \(\dfrac{1}{5}\) .  \(x\)  +\(\dfrac{5}{6}\)   (Tìm x)

Answer 1

\(\dfrac{3}{5}x+\dfrac{1}{2}=\dfrac{1}{5}x+\dfrac{5}{6}\\ \Rightarrow\dfrac{3}{5}x+\dfrac{1}{2}-\dfrac{1}{5}x-\dfrac{5}{6}=0\\ \Rightarrow\left(\dfrac{3}{5}x-\dfrac{1}{5}x\right)+\left(\dfrac{1}{2}-\dfrac{5}{6}\right)=0\\ \Rightarrow\dfrac{2}{5}x+\dfrac{3}{6}-\dfrac{5}{6}=0\\ \Rightarrow\dfrac{2}{5}x-\dfrac{2}{6}=0\\ \Rightarrow\dfrac{2}{5}x=\dfrac{2}{6}\\ \Rightarrow x=\dfrac{2}{6}:\dfrac{2}{5}\\ \Rightarrow x=\dfrac{2}{6}.\dfrac{5}{2}\\ \Rightarrow x=\dfrac{5}{6}\)