Question

\(\dfrac{2}{x}\)-\(\dfrac{5}{2-x}\)=\(\dfrac{3x+2}{x\left(x-2\right)}\)

Answer 1

\(\dfrac{2}{x}-\dfrac{5}{2-x}=\dfrac{3x+2}{x\left(x-2\right)}\) ĐKXĐ : \(\left\{{}\begin{matrix}x\ne0\\x\ne2\end{matrix}\right.\)

\(\Leftrightarrow\dfrac{2}{x}+\dfrac{5}{x-2}=\dfrac{3x+2}{x\left(x-2\right)}\)

\(\Leftrightarrow\dfrac{2\left(x-2\right)}{x\left(x-2\right)}+\dfrac{5x}{x\left(x-2\right)}=\dfrac{3x+2}{x\left(x-2\right)}\)

`=> 2x-4 + 5x=3x+2`

`<=> 7x-4=3x+2`

`<=> 7x-3x=2+4`

`<=> 4x=6`

`<=>x=6/4=3/2(t//m)`

Vậy pt có nghiệm `x=3/2`